关闭文件时出现“双重释放或损坏(输出)”?

时间:2019-01-17 15:58:06

标签: c file multidimensional-array malloc

我写了一段代码来处理各种参数(文件,动态二维数组,将指针传递给函数等),所以不要介意某些段落似乎没用。 在运行时,如果我输入了3行以上,则程序崩溃,并且终端显示“ Double free or destroy(out)”,然后创建了核心转储。该错误应在foo2中的fclose(fp)上发生。

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

void foo1(int *);
void foo2(int*,int,int**,FILE*);
void readfoo(FILE *, int **, int);

int main(void)
{
    FILE *fp;
    int **a, i, j, r, c, *pr, *pn, *pc;
    pc = &c;
    pr = &r;
    foo1(pr);
    a = malloc(r*sizeof(int));
    foo2(pc,r,a,fp);
    if((fp = fopen("column.txt", "r")) == NULL)
    {
        fprintf(stderr, "Error, can't open \"column.txt\"");
        exit(1);
    }
    for(i=0;i<r;i++)
    {
        fscanf(fp,"%d", &c);
        for(j=0; j<c; j++)
        {
            fprintf(stdout, "insert line %d column %d -> ", i+1, j+1);
            fscanf(stdin, "%d", &a[i][j]);
        }
    }
    if(fclose(fp) != 0)
    {
        fprintf(stderr, "Error, can't close \"column.txt\"");
        exit(1);
    }
    readfoo(fp,a,r);
    remove("column.txt");
    return(0);
}

void foo1(int *r)
{
    fprintf(stdout, "how many lines ? -> ");
    fscanf(stdin, "%d", r);
}

void foo2(int *c, int r, int **a, FILE *fp)
{
    int i,j, act_c;
    if((fp = fopen("column.txt", "w")) == NULL)
    {
        fprintf(stderr, "Error, can't open \"column.txt\"");
        exit(1);
    }
        for(i=0;i<r;i++)
    {
        fprintf(stdout, "how many columns for line %d? -> ", i+1);
        fscanf(stdin, "%d", c);
        fprintf(fp,"%d\n", *c);
        a[i] = malloc((*c)*sizeof(int));
    }
    if(fclose(fp) != 0)
    {
        fprintf(stderr, "Error, can't close \"column.txt\"");
        exit(1);
    }
}

void readfoo(FILE *fp, int **a, int r)
{
    int c, i, j;
    fprintf(stdout, "printing the matrix... \n");
    if((fp = fopen("column.txt", "r")) == NULL)
    {
        fprintf(stderr, "Error, can't open \"column.txt\"");
        exit(1);
    }
    for(i=0;i<r;i++)
    {
        fscanf(fp,"%d", &c);
        for(j=0; j<c; j++)
        {
            fprintf(stdout, "%d ", a[i][j]);
        }
        fprintf(stdout, "\n");
    }
    if(fclose(fp) != 0)
    {
        fprintf(stderr, "Error, can't close \"column.txt\"");
        exit(1);
    }
}

1 个答案:

答案 0 :(得分:1)

main()中,您可以

 a = malloc(r*sizeof(int));

那应该是错误的

 a = malloc(r*sizeof(int *));

如果您为a[i]分配值,则会调用UB,这可能是崩溃的真正原因