拆分和展平字符串列表

时间:2019-01-17 11:14:12

标签: python list

lst = [
  "Zambia",
  "Zimbabwe",
  "Suite,203,2880,Zanker,Rd,San,Jose,95134",
  "1496A,1st,and,2nd,Floor,19th,main,8th,crossSector,1,HSR,Layout,Bengaluru,560102",
]
我在这里有一个世界。有些是实际的单词,例如example(“赞比亚”),有些是句子的示例(“ Suite,203,2880,Zanker,Rd,San,Jose,95134”)

如何将它们转换为以下格式。

lst = [
  "Zambia",
  "Zimbabwe",
  "Suite",
  "203",
  "2880",
  "Zanker",
  "Rd",
  "San",
  "Jose",
  "95134,
  "1496A",
  "1st",
  "and",
  "2nd",
  "Floor",
  "19th",
  "main",
  "8th",
  "crossSector",
  "1",
  "HSR",
  "Layout",
  "Bengaluru",
  "560102",
  "g2crowd_badge2",
  "Created with Sketch."
]

我如何使用python将清单迷恋成这种格式

请看看这个。

3 个答案:

答案 0 :(得分:10)

尝试:

res = []    
for i in lst:
   res.extend(i.split(","))   

另一种选择是使用reduce

res = list(reduce(lambda a, b: a + b.split(','), lst, []))

答案 1 :(得分:6)

您可以使用列表推导,并split每个字符串。最后用itertools.chain将结果展平:

from itertools import chain
list(chain(*[i.split(',') for i in lst]))

['Zambia', 'Zimbabwe', 'Suite', '203', '2880', 'Zanker', 'Rd', 'San', 'Jose', 
 '95134', '1496A', '1st', 'and', '2nd', 'Floor', '19th', 'main', '8th', 
 'crossSector', '1', 'HSR', 'Layout', 'Bengaluru', '560102']

答案 2 :(得分:3)

给出lst =您上面的列表

flattened_list = [item for sublist in lst for item in sublist.split(",")]


来源