Question

我有一个简单的销售表，其中包含以下列和数据

表名称：销售

SALES_ID SALES_DATE SALES_PERSON SALES_TOTAL
       1 2019-01-02 Jones          5236.6
       2 2019-01-17 Jones          3324.26
       3 2019-01-03 Jim            2257.25
       4 2019-01-17 Jim            5232.21
       5 2019-01-13 Josh          3254.2
       6 2019-01-15 Josh           215.36

现在我的问题是，假设今天是2019年1月17日，如何使用单个查询字符串得出低于结果的结果？

`SALES_PERSON`, `TODAY_SALES`, `MONTH_TO_DATE_SALES`
Jones           3324.26        8560.86
Jim             5232.21        7489.46
Josh            0.00           3469.56

谢谢！

Answer 1

我修改了@Siva查询字符串，这是满足我问题的最终查询。非常感谢！

SELECT
    SALES_PERSON,
    IFNULL( ( SELECT SUM( SALES_TOTAL ) FROM SALES WHERE SALES_DATE = '2019-01-17' AND SALES_PERSON = sal.SALES_PERSON ), 0 ) AS TODAY_SALES,
    ( SELECT SUM( SALES_TOTAL ) FROM SALES WHERE MONTH ( SALES_DATE ) = '01' AND SALES_PERSON = sal.SALES_PERSON ) AS MONTH_TO_DATE_SALES 
FROM
    SALES AS sal 
GROUP BY
    SALES_PERSON

Answer 2

使用子查询获取此结果

select SALES_PERSON,      
IFNULL(( select SUM(SALES_TOTAL) from SALES where SALES_DATE = '2019-01-17' and SALES_PERSON = sal.SALES_PERSON  ),0) as TODAY_SALES,
IFNULL(( select SUM(SALES_TOTAL) from SALES where MONTH(SALES_DATE)='01' and SALES_PERSON = sal.SALES_PERSON  ),0) as MONTH_TO_DATE_SALES 
from SALES as sal

group by SALES_PERSON

Answer 3

您可以尝试执行子查询，然后对结果进行分组，以防万一您当天有不同的销售量而将其分组。

select sales_person,sum(today_sales),month_to_date
from
(SELECT a.sales_person,sum(a.sales_total) as today_sales,(select sum(sales_total)
                                         from sales b
                                         where year(b.sales_date)=year(a.sales_date) and month(b.sales_date)=month(a.sales_date)) as month_to_date
from sales as a
where a.sales_date=date(now())) c
group by sales_person,month_to_date
order by sales_person

Answer 4

您可以将内部联接与子查询一起用于月份销售

select a.SALES_PERSON, a.SALES_TOTAL, t.month_total 
from SALES a 
inner join (
  select SALES_PERSON, month(SALES_DATE) month, year(SALES_DATE) year, sum(SALES_TOTAL) month_total
  from SALES 
  group by SALES_PERSON
) t ON t.SALES_PERSON = a.SALES_PERSON 
      AND t.month = month(curdate())
        AND t.year =  year(curdate())
WHERE a.SALES_DATE = curdate()

MySQL Today和Month To Date查询

4 个答案: