Question

我有一个正在使用的CSV文件。我不想将其转换为具有键和值的对象。我希望能够创建更多数组来存储不同的值即温度哼小时 snowDepth等所有这些都是具有7个值的数组

现在，这就是将csv存储在数据数组中的方式

“ 2018年11月28日7：30,1128，-2.122,86.2,34.06,1.178,320.2,20.4”

“ 2018年11月28日7：45,1129，-2.325,85.6,34.54,1.771,325.5,30.72”

“ 2018年11月28日8：00,1130，-2.679,85.7,30.73,1.764,312.1,28.98”

“ 2018年11月28日8：15,1131，-2.872,88,34.55,1.073,306.6,25.65”

“ 2018年11月28日8：30,1132，-2.953,90.7,35.25,1.247,311.2,30.06”

“ 2018年11月28日8：45,1133，-3.064,93.3,35,1.449,312.6,30.13”

“ 2018年11月28日9：00,1134，-2.771,91.5,33.44,0.988,311,28.27”      长度：7

第一个列是时间戳记，第二个是记录号，第三个是温度，第四个是湿度，依此类推。

function get_Data(data) {
    "use strict";
    var fileData = new Array();
    data = data.split(/\r\n|\r|\n/);
    data = data.slice(Math.max(data.length - 7, 0));
    createGraph(data);
}

我想要这样的数组

Tem = [-2.122，-2.325，-2.679，-2.872 ...]

小时= [7：30、7：45、8：00、8：15 ...]

Answer 1

简单-每个逗号分别为map和split，然后查看它应属于哪个项目的索引：

var data = ["11/28/2018 7:30,1128,-2.122,86.2,34.06,1.178,320.2,20.4",
  "11/28/2018 7:45,1129,-2.325,85.6,34.54,1.771,325.5,30.72",
  "11/28/2018 8:00,1130,-2.679,85.7,30.73,1.764,312.1,28.98",
  "11/28/2018 8:15,1131,-2.872,88,34.55,1.073,306.6,25.65",
  "11/28/2018 8:30,1132,-2.953,90.7,35.25,1.247,311.2,30.06",
  "11/28/2018 8:45,1133,-3.064,93.3,35,1.449,312.6,30.13",
  "11/28/2018 9:00,1134,-2.771,91.5,33.44,0.988,311,28.27",
];

var items = {
  date: [],
  recordNumber: [],
  temperature: [],
  humidity: [],
  value5: [],
  value6: [],
  value7: [],
  value8: [],
};

Object.keys(items).forEach((key, index) => items[key].push(data.map(str => str.split(",")[index])));

console.log(items);

Answer 2

尝试一下，它应该可以工作。我知道数据的位置，因此很容易拆分和查找条款和日期

var csv = document.getElementById("csvFile").innerHTML ;



function get_Data(data) {
    var result = {terms:[], hours:[] }
    var r = data.split(/\r\n|\r|\n/);

    r.forEach(function(element) {
    if (element !== "" && element.length>1){
      var term = element.split(",")[2]
      var date = new Date(element.split(",")[0])
      var hour =  date.getHours() + ":" + (date.getMinutes()<=9 ? "0" + date.getMinutes() : date.getMinutes());
      
      result.terms.push(term);
      result.hours.push(hour)
      }
    });
 return result;
} 

console.log( get_Data(csv))

<div id="csvFile" style="display:none;">
11/28/2018 7:30,1128,-2.122,86.2,34.06,1.178,320.2,20.4
11/28/2018 7:45,1129,-2.325,85.6,34.54,1.771,325.5,30.72
11/28/2018 8:00,1130,-2.679,85.7,30.73,1.764,312.1,28.98
11/28/2018 8:15,1131,-2.872,88,34.55,1.073,306.6,25.65
11/28/2018 8:30,1132,-2.953,90.7,35.25,1.247,311.2,30.06
11/28/2018 8:45,1133,-3.064,93.3,35,1.449,312.6,30.13
11/28/2018 9:00,1134,-2.771,91.5,33.44,0.988,311,28.27
</div>

Answer 3

您正在混淆一些事情。 fileData在做什么（似乎未使用）？而且slice是执行此操作的不正确方法。

相反，请尝试：

function get_Data(csv) {
    csv = csv.replace(/[\r\n]+/gi,"\n"); // reduce line endings into single LF chars
    rows = csv.split("\n"); // split into array of rows
    var result = [];
    for (var i in rows) result.push(rows[i].split(",")); // split each row
    return result;
}

（编辑）如果仅需要CSV数据的最后X行，请使用：

function get_Data(csv,lastNumRows) { // get only the last <lastNumRows> rows
    csv = csv.replace(/[\r\n]+/gi,"\n"); // reduce line endings into single LF chars
    rows = csv.split("\n").slice(-lastNumRows); // split into array of rows
    var result = [];
    for (var i in rows) result.push(rows[i].split(",")); // split each row
    return result;
}

如何解析存储在数组中的数据

3 个答案: