Question

我是宇宙的新手，我有一个收藏夹，我试图查询下面的示例。因为数据的本质是嵌套的。我们还必须能够查询文档的子部分。

我在尝试检索以下集合中itemCode的数据时陷入困境。

任何信息都会有很大帮助。预先感谢。

选择*来自c 其中c.customerSites.pricingGroup.itemCode =“ 2400953”

此查询没有返回结果。

{
     "customerSites": [
    {
        "customerCode": "196729",
        "businessUnitName": "XXXXX SOUTHERN LTD",
        "siteCode": "96271",
        "addressCode": "_MAINXXXX",
        "pricingGroup": [
            {
                "itemCode": 2400953,
                "branches": [
                    8999,
                    3001,
                    3002,
                    3003,
                    3004
                ],
                "rates": [
                    {
                        "branchCodes": [
                            8999,
                            3001,
                            3002,
                            3003
                        ],
                        "discountPercentage": null,
                        "derivedRateId": 77735584,
                        "derivedRateClassification": "customrate",
                        "branchLevel": 109,
                        "derivedRateType": "P",
                        "durationRates": [
                            {
                                "durationType": 1,
                                "rate": 125
                            }
                        ]
                    }
                ]
            }
        ]
    }
],
"id": "196729",
"dataType": "AccountCustomer",
"_ts": 1547161022

}

Answer 1

只需：

//this is the php code with the call to the table with the images

<div class="display_CNC_Machining_images">
    <?php
    include_once 'includes/dbh.inc.php';

    $sql = "SELECT * FROM gallery WHERE image_category = 'CNC_Machinery'";
    $stmt = mysqli_stmt_init($conn);
    if (!mysqli_stmt_prepare($stmt,$sql)) {
      echo 'SQL statement failed!';
    } else {
      mysqli_stmt_execute($stmt);
      $result = mysqli_stmt_get_result($stmt);

      while ($row = mysqli_fetch_assoc($result)) {


//what's echoed out by the database

        echo '  <a class="images" style="background-repeat:no-repeat; background-image: url(gallery/'.$row["imgFullNameGallery"].')">
                <div class="color-overlay">
                <h3>'.$row["titleGallery"].'</h3>
                <p>'.$row["descGallery"].'</p>
                </div>
                </a>';
      }
    }
    ?>
</div>

查询数组数据的Cosmos db集合

1 个答案: