如何从数组中获取匹配的元素？

Question

试图获得低于预期的结果，但没有进入specialtyMembers的for循环中的任何想法，如何获得与两个数组匹配的预期响应，是否有使用过滤器的方法？

main.js

const members = [{
    "indexId": "1",
    "planId": "8304TDMACC001"
}]

const specialtyMembers = [{
        "proxyId": "",
        "internalID": "38482099",
        "externalID": "",
        "indexID": "1",
        "gender": "Male"
    },
    {
        "proxyId": "",
        "internalID": "38482100",
        "externalID": "",
        "indexID": "2",
        "gender": "Female"
    }
]

if (members) {
    const membersArray: any = [];
    for (const member of members) {
        if (specialtyMembers) {
            for (const cacheMember of specialtyMembers) {
                if (member.indexId === cacheMember.indexID) {
                    membersArray.push(cacheMember);
                }
            }
        }
    }
    specialtyMembers = membersArray;
}

预期的输出，因为indexId仅与此匹配

 [{
        "proxyId": "",
        "internalID": "38482099",
        "externalID": "",
        "indexID": "1",
        "gender": "Male"
    }
]

Answer 1

通过filter数组specialtyMembers就像这样：

specialtyMembers = specialtyMembers.filter(e => members[0].indexId == e.indexID);

注意：您必须将specialtyMembers从常量更改为变量。为此，请在此行中将const更改为var：

var specialtyMembers = [{...}, {...}];

演示：

const members = [{
  "indexId": "1",
  "planId": "8304TDMACC001"
}];

var specialtyMembers = [{
    "proxyId": "",
    "internalID": "38482099",
    "externalID": "",
    "indexID": "1",
    "gender": "Male"
  },
  {
    "proxyId": "",
    "internalID": "38482100",
    "externalID": "",
    "indexID": "2",
    "gender": "Female"
  }
];

specialtyMembers = specialtyMembers.filter(e => members[0].indexId == e.indexID);

console.log(specialtyMembers);

编辑：

如果members中有多个元素，则只需要像这样创建indexId的数组即可：

var indexIds = members.map(e => e.indexId);

然后将filter语句更改为此：

specialtyMembers = specialtyMembers.filter(e => indexIds.includes(e.indexID));

演示：

const members = [{
  "indexId": "1",
  "planId": "8304TDMACC001"
}];

var specialtyMembers = [{
    "proxyId": "",
    "internalID": "38482099",
    "externalID": "",
    "indexID": "1",
    "gender": "Male"
  },
  {
    "proxyId": "",
    "internalID": "38482100",
    "externalID": "",
    "indexID": "2",
    "gender": "Female"
  }
];

var indexIds = members.map(e => e.indexId);

specialtyMembers = specialtyMembers.filter(e => indexIds.includes(e.indexID));

console.log(specialtyMembers);

Answer 2

使用reduce可以使用filter使用specialtyMembers = members.reduce((acc, ele) => { const filteredArr = specialtyMembers.filter(x => ele.indexId === x.indexID) return filteredArr.length > 0 ? acc.concat(filteredArr) : acc; }, []) 创建一个新数组，其中只有在您的条件下通过的元素：

sap.m.Input

Answer 3

const members = [{
  "indexId": "1",
  "planId": "8304TDMACC001"
}]

const specialtyMembers = [{
    "proxyId": "",
    "internalID": "38482099",
    "externalID": "",
    "indexID": "1",
    "gender": "Male"
  },
  {
    "proxyId": "",
    "internalID": "38482100",
    "externalID": "",
    "indexID": "2",
    "gender": "Female"
  }
]


if (members) {
  let memberIndexes = new Set(members.map(m => m.indexId))

  let result = specialtyMembers ? specialtyMembers.filter(m => memberIndexes.has(m.indexID)) : []
  console.log(result)

}