Question

我有两个相同的表，大部分数据都是相同的

Table 1
-------------------------------
     C1    C2    C3    C4    C5
R1   1     2     3     4     5
R2   6     7     8     9     10

Table 2
-------------------------------
     C1    C2    C3    C4    C5
R1   1     2     3     4     5
R2   6     17    18    9     10
R3   11    12    13    14    15
R4   16    17    18    19    20

有人可以帮我编写查询以比较两个表，在结果集中获取R3，R4，还可以获取列值不同的行，例如C2R2，C3R2

Answer 1

假设第一列（值为R1，R2等）被命名为row（您不用说）：

select row, 'Not present in table 2' as difference
from table_1
where row not in (select row from table_2)
union all
select row, 'Not present in table 1'
from table_2
where row not in (select row from table_1)
union all
select
  t1.row,
  concat(
    case when t1.c1 <> t2.c1 then 'c1 ' end,
    case when t1.c2 <> t2.c2 then 'c2 ' end,
    case when t1.c3 <> t2.c3 then 'c3 ' end,
    case when t1.c4 <> t2.c4 then 'c4 ' end,
    case when t1.c5 <> t2.c5 then 'c5 ' end
  )
from table_1 t1
join table_2 t2 on t1.row = t2.row
where t1.c1 <> t2.c1
   or t1.c2 <> t2.c2
   or t1.c3 <> t2.c3
   or t1.c4 <> t2.c4
   or t1.c5 <> t2.c5

比较两个表并返回具有不同值的行

1 个答案: