从python访问带有指针的C ++函数

Question

我正在尝试使用需要指向类的指针的函数。

我收到以下错误

<class 'Boost.Python.ArgumentError'>: Python argument types in
    G4TessellatedSolid.AddFacet(G4TessellatedSolid, G4TriangularFacet)
did not match C++ signature:
    AddFacet(G4TessellatedSolid {lvalue}, G4VFacet*)

G4TesselledSolid具有功能      G4bool AddFacet（G4VFacet * aFacet）

G4TriansularFacet类定义有      G4TriangularFacet类：公共G4VFacet

我的Boost类定义如下

class_<G4TessellatedSolid, G4TessellatedSolid*, boost::noncopyable>
         ("G4TessellatedSolid", "solid class")
 // ---
       .def("AddFacet",       &G4TessellatedSolid::AddFacet)
 // operators
       .def(self == self)
       ;

我的Python看起来像     棋盘格= G4TessellatedSolid（）     tessellate.AddFacet（face）

Answer 1

通过为定义添加碱基可以解决参考

 class_<G4VFacet, G4VFacet*, boost::noncopyable>
    ("G4VFacet", "solid class", no_init)
    // ---
    .def("SetVertex",      &G4TriangularFacet::SetVertex)

    // operators
    .def(self == self)
    ;

 class_<G4TriangularFacet, bases<G4VFacet> , boost::noncopyable>
   ("G4TriangularFacet", "solid class")
   // ---
   .def("SetVertex",      &G4TriangularFacet::SetVertex)

   // operators
   .def(self == self)
   ;