Question

因此，我在输入地址时使用Google API在下拉列表中显示位置列表。

当我单击下拉菜单中的选项/地址之一时，我希望警报触发并显示“嗨”。最好的方法是什么？

更多信息：

下拉菜单中的每个项目都具有'pac-item'类，并且位于'pac-container'的div内：

<div class="pac-container pac-logo" style="width: 601px; position: absolute; left: 15px; top: 70px; display: none;">
  <div class="pac-item"><span class="pac-icon pac-icon-marker"></span><span class="pac-item-query"><span class="pac-matched">S</span>ão Paulo</span><span>State of São Paulo, Brazil</span></div>
  <div class="pac-item"><span class="pac-icon pac-icon-marker"></span><span class="pac-item-query"><span class="pac-matched">S</span>an Francisco</span><span>CA, USA</span></div>
</div>

所以我一直在尝试通过类名来获取Elements，然后当您单击其中一个元素时，它应该警告“ hi”

但是，由于下拉菜单中的项直到您单击输入后才加载，我认为这会在页面加载和Javascript试图通过其类名获取元素时引起问题。

解决此问题的最佳方法是什么？

<!DOCTYPE html>
<html lang="en">
  <head>
    <meta charset="UTF-8" />
    <meta name="viewport" content="width=device-width, initial-scale=1.0" />
    <meta http-equiv="X-UA-Compatible" content="ie=edge" />
    <link rel="stylesheet" href="style.css" />
    <link
      rel="stylesheet"
      href="https://stackpath.bootstrapcdn.com/bootstrap/4.2.1/css/bootstrap.min.css"
      integrity="sha384-GJzZqFGwb1QTTN6wy59ffF1BuGJpLSa9DkKMp0DgiMDm4iYMj70gZWKYbI706tWS"
      crossorigin="anonymous"
    />

    <script
      src="https://code.jquery.com/jquery-3.3.1.slim.min.js"
      integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo"
      crossorigin="anonymous"
    ></script>
    <script
      src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.6/umd/popper.min.js"
      integrity="sha384-wHAiFfRlMFy6i5SRaxvfOCifBUQy1xHdJ/yoi7FRNXMRBu5WHdZYu1hA6ZOblgut"
      crossorigin="anonymous"
    ></script>
    <script
      src="https://stackpath.bootstrapcdn.com/bootstrap/4.2.1/js/bootstrap.min.js"
      integrity="sha384-B0UglyR+jN6CkvvICOB2joaf5I4l3gm9GU6Hc1og6Ls7i6U/mkkaduKaBhlAXv9k"
      crossorigin="anonymous"
    ></script>

    <title>Document</title>
  </head>
  <body>
    <div class="col-md-6">
      <form id="distance_form">
        <div class="form-group"><label>Origin: </label> <input class="form-control" id="from_places" placeholder="Enter a location" />
          <input id="origin" name="origin" required="" type="hidden" />
        </div>
      </form>
    </div>
    <script>

      $(function () {
        // add input listeners
        google.maps.event.addDomListener(window, "load", function () {
          var from_places = new google.maps.places.Autocomplete(
            document.getElementById("from_places")
          );
        });
         console.log(document.getElementsByClassName("pac-item"))

         let googleDropDown = document.getElementsByClassName("pac-item")

         googleDropDown.addEventListener('click', alert)

         function alert(){
           alert('hi')
         }
      });

    </script>

    <script async defer src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&libraries=places&language=en"></script>
  </body>
</html>

编辑：

将其包装在google.maps.event.addDomListener内可以使我将各项记录到控制台，但也会导致以下错误：

Answer 1

您可以使用.on（）函数确保当前元素和将来的元素将处理您的click事件

  $(function () {
    // add input listeners
    google.maps.event.addDomListener(window, "load", function () {
      var from_places = new google.maps.places.Autocomplete(
        document.getElementById("from_places")
      );
    });

     $("body").on("click", ".pac-container > .pac-item", function() {
         alert('hi');
     });
  });

单击google下拉项时触发警报

1 个答案: