我什至无法结束这个结束声明而没有错误
import java.util.Arrays;
BufferedReader dataIn=new BufferedReader (new InputStreamReader (System.in));
String a;
int n=0;
int array []= {98,9,212,21,11,49,63,70,100};
System.out.print("My Values "+Arrays.toString(array));
System.out.print("\nEnter Number: ");
a=dataIn.readLine();
array[n]=Integer.parseInt(a);
if(array[n]==98) {
System.out.print("The Index Number is 0");
}
if(array[n]==9) {
System.out.print("The Index Number is 1");
}
if(array[n]==212) {
System.out.print("The Index Number is 2");
}
}
else{
System.out.print("Error");
}// how to end this?
// if correct the correct index number will go
// if wrong error
}
}
答案 0 :(得分:1)
您在}
之前有一个else
,并且需要进行else/if
的构建
if (array[n] == 98) {
System.out.print("The Index Number is 0");
} else if (array[n] == 9) {
System.out.print("The Index Number is 1");
} else if (array[n] == 212) {
System.out.print("The Index Number is 2");
} else {
System.out.print("Error");
}
用于:要索引的值的常规方法是:
String valueStr = dataIn.readLine();
int value = Integer.parseInt(valueStr);
boolean found = false;
for (int i = 0; i < array.length; i++) {
if (array[i] == value) {
System.out.println("The index number is " + i);
found = true;
break;
}
}
if (!found) {
System.out.println("Error");
}