Question

我正在使用date_trunc将Unix时间转换为更具可读性的格式。但是，“小时”的值返回带后缀0的年份和小时。我希望该格式在军事时间仅显示hh：mm。我该如何实现？

SELECT
    actor_id AS SRT_ID,
    shift_date,
    DATE_TRUNC('hour', from_unixtime(shift_start)) AS login,
    DATE_TRUNC('hour', from_unixtime(shift_end)) AS logout
FROM
    fct_rep_schedule_details
WHERE
    ds BETWEEN '2018-12-01' AND '2019-01-15'
GROUP BY 1,2,3,4

例如，我希望输出为13:00而不是2019-01-22 13:00:00.000。

Answer 1

您不想截断日期。您要提取小时/时间。您可以使用cast()提取时间：

SELECT actor_id AS SRT_ID,
       shift_date,
       DATE_TRUNC('hour', from_unixtime(shift_start)) AS login,
       DATE_TRUNC('hour', from_unixtime(shift_end)) AS logout,
       CAST(from_unixtime(shift_start) as time) AS login_hh,
       CAST(from_unixtime(shift_end) as time) AS logout_hh,
FROM fct_rep_schedule_details
WHERE ds BETWEEN '2018-12-01' AND '2019-01-15';

如果要控制时间的格式，请使用to_char()：

SELECT actor_id AS SRT_ID,
       shift_date,
       DATE_TRUNC('hour', from_unixtime(shift_start)) AS login,
       DATE_TRUNC('hour', from_unixtime(shift_end)) AS logout,
       TO_CHAR(from_unixtime(shift_start), 'HH:MI') AS login_hh,
       TO_CHAR(from_unixtime(shift_end), 'HH:MI') AS logout_hh,
FROM fct_rep_schedule_details
WHERE ds BETWEEN '2018-12-01' AND '2019-01-15';

Answer 2

您想要格式化日期，而不是缩短日期。您应该可以使用以下查询来格式化时间：

SELECT
    actor_id AS SRT_ID,
    shift_date,
    DATE_FORMAT(from_unixtime(shift_start), '%H:%i') AS login,
    DATE_FORMAT(from_unixtime(shift_end), '%H:%i')  AS logout
FROM
    fct_rep_schedule_details
WHERE
    ds BETWEEN '2018-12-01' AND '2019-01-15'
GROUP BY 1,2,3,4

其中%H转换为00 .. 23中的小时，%i转换为分钟，根据prestoDB documentation

将Unix日期转换为24小时ISO格式

2 个答案: