Question

我在Powershell中有一个变量，该变量返回以下字符串

class Home extends Component {
  constructor(props) {
    super(props);
  }

  componentDidMount() {
    this.props.actions.getProgramsStart();
  }
  render() {
  const { ProgramsLoading, programs } = this.props.state;
  //check if you are loading, so you dont need to apply filters or whatever you add (filter/map creates a new array each time)
  if(ProgramsLoading) return <div><Loader style={{ display: "block" }} content="Program List loading" /></div>

  const defaultValue = {SeriesFilterData: [], MoviesFilterData =[]}
  const reducerFunction = (accum, currentValue)=>{
      //if this check is an AND for all the cases, return directly if the item doesnt match.
      if(currentValue.releaseYear < 2010) return accum;
      if(currentValue.programType==="series"){
         accum.SeriesFilterData.push(currentValue);
      } else if(currentValue.programType==="movie"){
         accum.MoviesFilterData.push(currentValue);
      }
      return accum;
  }
  const results = programs.reduce( reducerFunction, defaultValue);
    // using {...result} will destructure to be (SeriesFilterData, MoviesFilterData) separeted props
    return (
      <div id="home">
          <h1>program data</h1>
          <SomeComponent {...resulst} /> 
      </div>
    );
  }
}

我正在尝试将该字符串格式化为类似（甚至在csv文件中）的格式：

    S: Title = test S: Title = test2 S: Title = test3 S: Title = test4 
 TE: 2019-01-19T00:00:00Z TE: 2019-01-20T00:00:00Z TE: 2019-01-22T00:00:00Z TE: 2019-01-23T00:00:00Z

但没有成功。我该怎么办？

编辑：这是生成字符串的行。基本上，我想提取一个keepass数据库中所有条目的名称和到期日期（我可能已经找到了另一种使用导出的xml文件的方法）：

test        test2        test3       test4
2019-01-19  2019-01-20   2019-01-22  2019-01-23

Answer 1

我必须承认.replace()的使用有点过分，但并没有太多用处：

$mystring= "    S: Title = test S: Title = test2 S: Title = test3 S: Title = test4 
 TE: 2019-01-19T00:00:00Z TE: 2019-01-20T00:00:00Z TE: 2019-01-22T00:00:00Z TE: 2019-01-23T00:00:00Z "


$MyString.trim().replace(" S: Title = ",",").replace("T00:00:00Z TE: ",",").replace("TE: ","").replace("S: Title = ","").replace("T00:00:00Z","").replace(" ","") | convertfrom-csv

输出：

test         test2        test3        test4     
----         -----        -----        -----     
2019-01-19   2019-01-20   2019-01-22   2019-01-23

在创建字符串时执行这些步骤会更容易（也更容易监控）。

在Powershell中解析字符串并创建一个表

1 个答案: