Question

payload.json

  {
 "channelData": {
"data": "CHANNEL_DATA",
"salesChannel": "WEB",
"createdBy": "WEBSITE",
"accountId": "#(accountId)",
"sessionId": "#(accountname)"
 }
}

Request.feature

@ignore
Feature:

 Scenario:

  * def Request = read('../payload.json')
  * def headersData = { "Content-Type" : "application/json"}
   Given url BaseUrl + '/account/'+'#(accountId)'
   And request Request
   And headers headersData
   When method post
   Then status 200

account.feature

 @ignore
 Feature:

Scenario:
  * print temp
  * def headersData = { "Content-Type" : "application/json"}
   Given url BaseUrl + '/accountdata/'
   And request temp
   And headers headersData
   When method post
   Then status 200

帐户令牌功能

  Feature: 
  Scenario: identify the reference account

 * def reqRes = karate.call('../Request.feature')
 * def temp =  karate.pretty(reqRes)
 * def account = karate.call('../requests/account.feature',{temp : temp })

我想将Request.feature的响应作为account.feature的请求有效负载传递。当我尝试上述情况时，temp的值将打印在数组中。 [Request.feature的#response]如何解决此问题。

Answer 1

请仔细研究该示例，它将回答您遇到的所有问题，并且您会发现问题出在哪里：call-feature.feature

例如，要从response结果中提取call，您必须对其进行“解压”：

Scenario: create kittens
    * def result = call read('create-two-cats.feature')
    * def temp = result.response

如何将一个功能的完整响应作为请求传递给另一个功能

1 个答案: