我正在尝试在Android Studio中编写单元测试代码。
在调试模式下,当我到达断点时,我具有以下变量:
token!!.length = 392
以下断言永远不会成立:
assertEquals(392, token!!.length)
我不知道那怎么可能。
“运行”输出为:
java.lang.AssertionError:
Expected :392
Actual :0
<Click to see difference>
at org.junit.Assert.fail(Assert.java:88)
at org.junit.Assert.failNotEquals(Assert.java:834)
at org.junit.Assert.assertEquals(Assert.java:118)
at org.junit.Assert.assertEquals(Assert.java:144)
at com.activity.screen.myapp.ExampleUnitTest.get_auth_token_isCorrect(ExampleUnitTest.kt:70)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:78)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:57)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268)
at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
at org.junit.runner.JUnitCore.run(JUnitCore.java:137)
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:68)
at com.intellij.rt.execution.junit.IdeaTestRunner$Repeater.startRunnerWithArgs(IdeaTestRunner.java:47)
at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:242)
at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:70)
janv. 16, 2019 2:29:40 PM okhttp3.internal.platform.Platform log
INFOS: --> POST https://theauthwebsite/api/auth/token http/1.1
Process finished with exit code -1
源代码:
var token: String? = ""
var user = user("support@mycompany.fr","aaaabbbb", "1")
AuthService.getAuthToken(user).enqueue(object : Callback<Result> {
override fun onResponse(call: Call<Result>, response: Response<Result>) {
if (response.isSuccessful) {
token = response.body()!!.result!!.token
}
}
override fun onFailure(call: Call<Result>, t: Throwable) {
token = "";
}
})
assertEquals(392, token!!.length) // Here token really has a length of 392 so that it should be ok but it is not
}
编辑:解决方案是使用同步请求,因此代码被以下代码修改:
token = authServices.getAuthToken(user).execute().body()!!.result!!.token
assertEquals(392, token!!.length)
谢谢你们!
答案 0 :(得分:2)
您不等待结果。 enqueue()
方法异步执行请求。这意味着该回调将不会在同一线程上发生。进行enqueue()
调用后,断言将立即被调用。此时,尚未调用任何回调,因此token
的值尚未更改。如果要同步等待结果,请使用execute()
而不是enqueue()
。
答案 1 :(得分:2)
您断言为时过早。当测试到达断言时,异步令牌请求尚未完成。
enqueue()
闻起来像翻新。改用execute()
使通话同步。