Question

我正在尝试获取有关指定点胶日期的最新点胶日期的结果。为什么我的查询不起作用？

select 
visits.patient_visit_id,pv.patient_id,pv.dispensing_date as dispensing_date,pv.dose,pv.quantity,pv.duration as days,dc.drug,r.regimen_code
FROM v_patient_visits pv

left join drugcode dc on drug_id = dc.id
left join regimen r on r.id = pv.current_regimen
left join patient_status ps on ps.id = pv.current_status

inner join 
(SELECT patient_visit_id, max(dispensing_date) as max_dispensing_date
 FROM `v_patient_visits`
 GROUP BY patient_id
) as visits 
ON visits.patient_visit_id = pv.patient_visit_id AND
   visits.max_dispensing_date = pv.dispensing_date

where 
pv.dispensing_date <= '2018-12-31'
and regimen_service_type  = 'service one'
and ps.Name = 'Status one'

结果选择了正确的Patient_id，剂量，数量和天数，但分配日期不是最新的，参考<='2018-12-31'

v_patient_visits表如下：

patient_visit_id    patient_id  dispensing_date    dose    quantity    days    drug    current_regimen    current_status    regimen_service_type
48240   000001  2019-01-16    1OD    39    39    1    11    21    service one
48240   000001  2018-12-06    1OD    39    39    1    11    21    service one
48240   000001  2017-12-05    1OD    39    39    2    12    21    service one
48240   000001  2016-12-04    1OD    39    39    3    13    21    service one
48241   000002  2019-01-10    1BD    40    40    4    14    22    service two
48241   000002  2018-11-10    1BD    40    40    4    14    22    service two
48241   000002  2017-11-09    1BD    40    40    5    15    22    service two
48241   000002  2016-11-08    1BD    40    40    6    16    22    service two
48242   000003  2017-10-15    1OD    41    41    7    17    21    service one
48242   000003  2016-10-14    1OD    41    41    8    18    21    service one
48242   000003  2015-10-13    1OD    41    41    9    19    21    service one

同一个Patient_id可能有多个条目，我希望它选择最近的配药日期

药物代码表如下：

id    drug
1   Drug one
2   Drug two
3   Drug three
4   Drug four

方案表如下：

id  regimen_code
11  Regimen one
12  Regimen two
13  Regimen three
14  Regimen four

Patient_status表如下：

id    Name
21  Status one
22  Status two
23  Status three
24  Status four

我希望输出如何：

patient_visit_id    patient_id  dispensing_date    dose    quantity    days    drug    regimen_code
48240   000001  2018-12-06    1OD    39    39    Drug one    Regimen one
48242   000003  2017-10-15    1OD    41    41    Drug seven    Regimen seven

Answer 1

关闭。您需要在该日期加入子查询！

(SELECT patient_id, max(dispensing_date) as max_dispensing_date
 FROM `v_patient_visits`
 GROUP BY patient_id
) visits 
ON visits.patient_visit_id = pv.patient_visit_id AND
   visits.max_dispensing_date = pv.dispensing_date

SQL为每个记录选择最新日期

1 个答案: