Question

我有一个带有状态字段的Post表

t.string :state

我使用Classy Enum宝石通过State生成的类创建了我的3个状态

class State < ClassyEnum::Base
end

class State::New < State
end

class State::Published < State
end

class State::Hidden < State
end

我有一个具有更新方法的post_controller

我认为我有此表单来提交更改

<%= form_for @post, method: :patch do |f| %>
    <%= f.hidden_field state: "published" %>
    <%= f.submit "Share", class: "btn btn-primary"%>
<% end %>

为什么会出现此错误？

ActionView::Template::Error (undefined method `{:state=>"published"}' for #<Post:0x00007f973fe62ef8>)

Answer 1

在帖子模型中添加state:string

rails g migration add_state_to_posts state

或

class Post < ActiveRecord::Base
  include ClassyEnum::ActiveRecord

  classy_enum_attr :state

end

参考=> https://github.com/beerlington/classy_enum#3-setup-the-active-record-model

Answer 2

这是答案：

<%= link_to 'Publish', post_path, data: {method: :patch, remote: true, params: {state: "published"}.to_param}, class: "btn btn-primary" %>

如果有人可以帮助，我只需要form_for方式

form_for与classy_enum

2 个答案: