所以我有我运行的主要python脚本,并且基本上将-p
,-e
和-d
三个参数传递给另一个python脚本。为了理解这一点,我一直在使用subprocess
。
我要实现的不是使用subprocess
,而是要import
第二个文件'generate_json.py'
,并且能够将三个参数传递给它的main()
函数。如何像在subprocess
调用中那样传递三个参数?
我的主脚本代码如下:
import generate_json as gs
def get_json_location(username=os.getlogin()):
first = "/Users/"
last = "/Desktop/data-code/Testdata"
result = first + username + last
return result
答案 0 :(得分:0)
假定脚本文件不必单独使用,即:generate_json.py
可以从命令行上单独使用。
我认为更干净的方法是包装generate_json.py
函数并将其放入类中。
在这种情况下,我将generate_json.py
重命名为ConfigurationHandling.py
import os
import json
from functions import read_config
class ConfigurationHandler(object):
def __init__(self, new_parameter_file, new_export_data_file, new_export_date):
self._parameter_file = new_parameter_file
self._export_data_file = new_export_data_file
self._export_date = new_export_date
self._parsed_configuration = self.read_configuration()
self._perform_some_action1()
self._perform_some_action2()
def _read_configuration(self):
"""Uses lower level function `read_config` in function.py file to read configuration file"""
parsed_configuration = read_config(self.export_data_file)
return parsed_configuration
def _perform_some_action1(self):
pass
def _perform_some_action2(self):
# Logic code for parsing goes here.
pass
def get_config(self):
"""Returns configuration"""
return [self.parameter_file, self.parsed_configuration, self.export_date]
def json_work(self):
cfg = self.get_config()[0] # json location
data = self.get_config()[1] # export_agent_core_agent.yaml
date = self.get_config()[2] # synthetic data folder - YYYY-MM-DD
if not date:
date = ""
else:
date = date + "/"
json_location = cfg # json data path
json_database = data["config"]["database"]
json_collection = data["config"]["collection"]
json_path = "{0}/{1}{2}/{3}/{3}.json".format(json_location, date, json_database, json_collection)
json_base_name = json_database + "/" + json_collection + "/" + os.path.basename(json_path) # prints json filename
current_day = date
with open('dates/' + current_day + '.json', 'a') as file:
data = {}
if os.path.exists(json_path):
json_file_size = str(os.path.getsize(json_path)) # prints json file size
print("File Name:" " " + json_base_name + " " "Exists " + "\n")
print("File Size:" " " + json_file_size + " " "Bytes " "\n")
print("Writing to file")
# if json_path is not False:
data['File Size'] = int(json_file_size)
data['File Name'] = json_base_name
json.dump(data, file, sort_keys=True)
file.write('\n')
else:
print(json_base_name + " " "does not exist")
print("Writing to file")
data['File Name'] = json_base_name
data['File Size'] = None
json.dump(data, file, sort_keys=True)
file.write('\n')
file.close()
然后在main.py
from ConfigurationHandler import ConfigurationHandler
def main():
#Drive the program from here and add the functionality together.
#Routine to do some work here and get the required variables
parameter_file = "some_parameter"
export_data_file = "some_file.yaml"
new_export_date = "iso_8601_date_etc"
conf_handl = ConfigurationHandler(parameter_file, export_data_file, new_export_date)
configuration = conf_handl.get_config()
conf_handl.json_work()
if __name__ == '__main__':
main()
在项目中,您应该旨在仅拥有一个主要功能,并相应地拆分功能。
稍后,当所有内容均分后,更改程序的各个部分会容易得多。
答案 1 :(得分:0)
到目前为止,我有以下内容:
from genrate_jsonv2 import ConfigurationHandler
import os
import argparse
def get_json_location(username=os.getlogin()):
first = "/Users/"
last = "/Desktop/data-code/Testdata"
result = first + username + last
return result
def get_config():
parser = argparse.ArgumentParser()
parser.add_argument("-d", "--export-date", action="store", required=True)
args = parser.parse_args()
return [args.export_date]
yml_directory = os.listdir('yaml')
yml_directory.remove('export_config.yaml')
data = get_config()[0]
def main():
for yml in yml_directory:
parameter_file = get_json_location
export_data_file = yml
new_export_date = data
conf_handl = ConfigurationHandler(parameter_file, export_data_file, new_export_date)
configuration = conf_handl.get_config()
conf_handl.json_work()
if __name__ == '__main__':
main()
问题是在export_data_file内,我真的不想传递file_path位置,而是让它遍历yml目录中的每个file_name。这样做时,我收到一条错误消息,“读取配置文件时出错”