Question

PHP从5.2升级到5.6，以下代码停止工作：

运行后，抛出错误：无法加载资源：服务器以状态500（内部服务器错误）响应。我不确定javascript或PHP本身是否存在导致此问题的问题。前端正在加载，但未在回调中获取数据。

任何帮助将不胜感激。如果这是某些错误或帖子的重复，请指出必要的答案。如果我在写问题时犯了任何错误，请写评论，为什么要这样做，而不是公然给我打分。

JavaScript代码段：

 jQuery(document).ready(function() {        
            // Get data from Outlast Server
            var url="https://xxxxx/xxxx/q_data.php?callback=?";
            jQuery.getJSON(url,  function(rts_data) {
                var deck_count = 0, shiplap_count = 0, bnb_b_count = 0, bnb_c_count = 0;

                for(var i=0; i<rts_data.length; i++) {
                    if (rts_data[i].type == "Deck") {
                        data[0][deck_count] = new Object();
                        data[0][deck_count].productName = rts_data[i].productName;
                        data[0][deck_count].coverage    = rts_data[i].coverage;
                        data[0][deck_count].screws      = rts_data[i].screws;
                        data[0][deck_count].gaps        = rts_data[i].gaps;

                        // Insert the data into the Select Box
                        jQuery('#opt_d').append(jQuery('<option>', { value : deck_count }).text(rts_data[i].productName)); 

                        deck_count++;
                    }
                    else if (rts_data[i].type == "Shiplap") {
                        data[1][shiplap_count] = new Object();
                        data[1][shiplap_count].productName = rts_data[i].productName;
                        data[1][shiplap_count].coverage     = rts_data[i].coverage;
                        data[1][shiplap_count].screws       = rts_data[i].screws;
                        data[1][shiplap_count].gaps         = rts_data[i].gaps;

                        // Insert the data into the Select Box
                        jQuery('#opt_s').append(jQuery('<option>', { value : shiplap_count }).text(rts_data[i].productName)); 

                        shiplap_count++;
                    }
                    else if (rts_data[i].type == "Board and Batton - Cap") {
                        data[2][bnb_c_count] = new Object();
                        data[2][bnb_c_count].productName = rts_data[i].productName;
                        data[2][bnb_c_count].coverage   = rts_data[i].coverage;
                        data[2][bnb_c_count].screws         = rts_data[i].screws;
                        data[2][bnb_c_count].gaps       = rts_data[i].gaps;

                        // Insert the data into the Select Box
                        jQuery('#opt_bnb_c').append(jQuery('<option>', { value : bnb_c_count }).text(rts_data[i].productName)); 

                        bnb_c_count++;
                    }
                    else if (rts_data[i].type == "Board and Batton - Base") {
                        data[3][bnb_b_count] = new Object();
                        data[3][bnb_b_count].productName = rts_data[i].productName;
                        data[3][bnb_b_count].coverage   = rts_data[i].coverage;
                        data[3][bnb_b_count].screws         = rts_data[i].screws;
                        data[3][bnb_b_count].gaps       = rts_data[i].gaps;

                        // Insert the data into the Select Box
                        jQuery('#opt_bnb_b').append(jQuery('<option>', { value : bnb_b_count }).text(rts_data[i].productName)); 

                        bnb_b_count++;
                    }
                }

PHP：

<?php
// Connection data
$host = "xxxxxxx";
$username = "xxxxx";
$database = "xxxxx";
$password = "xxxxx";

// Opens a connection to a mySQL server
$connection = mysql_connect ($host, $username, $password);
if (!$connection) {
    die("Not connected : " . mysql_error());
}

// Set the active mySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
    die ("Can\'t use db : " . mysql_error());
}

// Set the where clause
$where = "";
switch(@$_GET['type']) {
    case 'shiplap':
        $where = "WHERE type = 'Shiplap'";
    break;

    case 'deck':
        $where = "WHERE type = 'Deck'";
    break;

    case 'bnb_base':
        $where = "WHERE type = 'Board and Batton - Base'";
    break;

    case 'bnb_cap':
        $where = "WHERE type = 'Board and Batton - Cap'";
    break;

    default:
        $where = "";
    break;
}

// Run the query
$query = "SELECT * FROM `site_products` {$where} ORDER BY productID ASC";
$result = mysql_query($query);

if (!$result) {
    die("Invalid query: " . mysql_error());
}

// Declare Variables
$data_shiplap   = array();
$shiplap_i      = 0;

// Get the data and divide
while ($row = @mysql_fetch_assoc($result)) {
    $data_shiplap[$shiplap_i]['productName']    = $row['productName'];
    $data_shiplap[$shiplap_i]['coverage']       = $row['coverage'];
    $data_shiplap[$shiplap_i]['screws']         = $row['screws'];
    $data_shiplap[$shiplap_i]['gaps']           = $row['gaps'];
    $data_shiplap[$shiplap_i]['type']           = $row['type'];

    $shiplap_i++;
}

echo $_GET['callback']. '('. json_encode($data_shiplap) . ')'; 
?>

Answer 1

在PHP 5.6。*之后，所有std::transform函数均已弃用。我认为这就是为什么您得到{ std::string str( "HelLo" ); std::cout << str << '\n'; std::transform( str.begin(), str.end(), str.begin(), ::toupper ); std::cout << str << '\n'; std::transform( str.begin(), str.end(), str.begin(), ::tolower ); std::cout << str << '\n'; }的原因。将所有mysql_*函数替换为Internal server error，然后查看错误是否持续存在。

无法加载资源：PHP和jQuery回调

1 个答案: