Question

我的目标是将Markdown转换为文本。我通过使用Redcarpet将markdown解析为HTML，然后使用#strip_tags来完成此操作。我的问题是链接，此方法仅保留链接的文本，而不保留链接本身。

例如：使用#strip_tags后，我需要保留href网址

# current
<a href="http://www.google.com">google</a> => google
# desired
<a href="http://www.google.com">google</a> => http://www.google.com google

我认为最好的方法是使用正则表达式，有人可以帮助实现吗？

我的目标是：

def contents_md

# instantiates Redcarpet
    @markdown ||= begin
        options = [autolink: true, fenced_code_blocks: true,     no_intra_emphasis: true, hard_wrap: true, filter_html: true, gh_blockcode: true]
        renderer = Redcarpet::Render::HTML.new(render_options = {})
        Redcarpet::Markdown.new(renderer, *options)
    end

# I need to run contents through a regex before passing to renderer that will turn something like this:
# [text1](https://www.stackoverflow.com) and [text2](https://www.google.com)
# into:
# text1 https://www.stackoverflow.com and text2 https://www.google.com


# then ill pass the result here, which will preserve my links that would be held in <a></a> instead of losing them 
 @markdown.render(contents)
end

# this will then be ran like:
<%= strip_tags(value.contents_md) %>

Answer 1

您可以将gsub与这样的正则表达式一起使用：

text = "[text1](https://www.stackoverflow.com) and [text2](https://www.google.com)"

text.gsub(/\[(.*?)\]\((.*?)\)/, "#{$1} #{$2}")
#=> "text2 https://www.google.com and text2 https://www.google.com"

用文字和网址替换降价链接

1 个答案: