如果父级的ng-if为false,我需要ng-models为空
<label><input type="radio" ng-value="true" name="radio1" ng-model="response.answer1" /> Yes</label>
<label class="margin-radio"><input type="radio" ng-value="false" name="radio1" ng-model="response.answer1" /> No</label>
<div ng-if="response.answer1">
<input type="text" ng-model="response.answer2" />
</div>
当用户选择“是”时,出现文本输入,然后用户可以输入一些内容。如果他这样做,然后单击“否”,则文本输入将消失,但response.answer2中的值仍然保留,因此如果控件不存在,则希望将其设置为null(ng-if =“ false”)。>
感谢您的帮助!
答案 0 :(得分:0)
您可以使用ng-change指令
1.25
在控制器中:
do
sub lvl
level% = 1
levelup% = 50
experience% = 5
ExperTotal% = 0
if Expertotal% = levelup% then 'something here to add 1 to level%
while Expertotal% = levelup%
' multiply them both by 1.25
wend
loop
end sub
答案 1 :(得分:0)
要获得预期的结果,请使用ng-init分配null
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope) {
});
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.9/angular.min.js"></script>
<body>
<div ng-app="myApp" ng-controller="myCtrl">
<label><input type="radio" ng-value="true" name="radio1" ng-model="response.answer1" /> Yes</label>
<label class="margin-radio"><input type="radio" ng-value="false" name="radio1" ng-model="response.answer1" /> No</label>
<div ng-if="response.answer1">
<input type="text" ng-model="response.answer2" ng-init="response.answer2=null"/>
</div>
</div>
</body>
</html>