I need to find the maximum recurrence in a number and I seem to have figured out all other test cases besides testcase on line 31 in test_sweep.
I have tried to rewrite this but I am fairly certain my code should work.
def max_run(l: list) -> list:
if len(l) <= 0:
return 0
if len(l) == 1:
return 1
bal = 0
maxbal = 0
compare_item = l[0]
for item in l:
if item == compare_item:
bal = bal + 1
else:
compare_item = item
if bal >= maxbal:
maxbal = bal
bal = 1
return maxbal
class TestMaxRun(unittest.TestCase):
def test_run(self):
before = [1, 1, 3, 3, 3, 5]
saved = before.copy()
self.assertEqual(sweep.max_run(before), 3)
self.assertEqual(before, saved)
self.assertEqual(sweep.max_run([]), 0)
self.assertEqual(sweep.max_run([42]), 1)
self.assertEqual(sweep.max_run([1, 2, 3]), 1)
self.assertEqual(sweep.max_run([3, 3, 3, 2, 3]), 3)
self.assertEqual(sweep.max_run([1, 2, 2, 3]), 2)
self.assertEqual(sweep.max_run([3, 4, 5, 5, 5]), 3)
Should pass all errors. max_run fails on line 31.
答案 0 :(得分:0)
您的问题是,您没有正确处理输入结尾处的长序列。在最后一个测试用例中,三个5的序列将被忽略,因为您无需检查它是否比之前的最长序列(长度为1)更长。
您需要在readarray num1 < file1 | awk -F'[ ]' '{print $1}'
while read -r $num1;
do grep "$num1" file2
echo "$num1" | awk -F':' '{print $1,$5}'
done < file3.txt
之前的max_run
循环外重复此代码:
return maxbal