Question

import bs4 as bs
import urllib.request
import re
import os
from colorama import Fore, Back, Style, init

init()

def highlight(word):
    if word in keywords:
      return Fore.RED + str(word) + Fore.RESET
    else:
      return str(word)

for newurl in newurls:
 url = urllib.request.urlopen(newurl)
 soup1 = bs.BeautifulSoup(url, 'lxml')
 paragraphs =soup1.findAll('p')
 print (Fore.GREEN + soup1.h2.text + Fore.RESET)
 print('')
 for paragraph in paragraphs:
    if paragraph != None:
        textpara = paragraph.text.strip().split(' ')
        colored_words = list(map(highlight, textpara))
        print(" ".join(colored_words).encode("utf-8")) #encode("utf-8")
    else:
        pass

我将列出关键词和网址列表。在网址中运行了几个关键字后，我得到了这样的输出

b'\x1b[31mthe desired \x1b[31mmystery corners \x1b[31mthe differential . 
\x1b[31mthe back \x1b[31mpretends to be \x1b[31mthe'

我删除了encode（“ utf-8”）并出现编码错误

Traceback (most recent call last):
 File "C:\Users\resea\Desktop\Python Projects\Try 3.py", line 52, in 
 <module>
   print(" ".join(colored_words)) #encode("utf-8")
  File "C:\Python34\lib\site-packages\colorama\ansitowin32.py", line 41, in 
   write
  self.__convertor.write(text)
   File "C:\Python34\lib\site-packages\colorama\ansitowin32.py", line 162, 
   in write
    self.write_and_convert(text)
   File "C:\Python34\lib\site-packages\colorama\ansitowin32.py", line 190, 
  in write_and_convert
  self.write_plain_text(text, cursor, len(text))
  File "C:\Python34\lib\site-packages\colorama\ansitowin32.py", line 195, in 
   write_plain_text
  self.wrapped.write(text[start:end])
   File "C:\Python34\lib\encodings\cp850.py", line 19, in encode
   return codecs.charmap_encode(input,self.errors,encoding_map)[0]
   UnicodeEncodeError: 'charmap' codec can't encode character '\u2019' in 
   position 23: character maps to <undefined>

我要去哪里错了？

Answer 1

我知道我要建议的不是“解决方案”，而是更多的解决方法，但是我一次又一次地因必须处理“对此编码”的各种奇怪字符而感到沮丧“编码”，有时成功，但很多时候却失败。

根据您newurl中使用的文本类型，问题字符的范围可能很有限。因此，我将视具体情况进行处理：每当我遇到这些错误之一时，我都会这样做：

import unicodedata
unicodedata.name('\u2019')

以您为例，您将获得以下信息：

'RIGHT SINGLE QUOTATION MARK'

旧的，讨厌的，正确的单引号...因此，as suggested here，我只是用一个看起来像它的讨厌的字符替换了那个讨厌的字符，但没有引发错误；根据您的情况

colored_words = list(map(highlight, textpara)).replace(u"\u2019", "'") # or some other replacement character

应该工作。然后您冲洗并在每次出现此错误时重复一次。诚然，这不是最优雅的解决方案，但是过了一会儿，您的newurl中所有可能的奇怪字符都被捕获，错误停止了。

Web抓取Python程序返回“'charmap'编解码器无法编码字符”

1 个答案: