Question

我正在创建一个小程序，该程序将启动msbuild来编译应用程序。我使用进程，但无法获取所生成的错误。如果我从cmd消息中以红色显示的状态启动msbuild，则我理解ErrorDataReceived事件应该检测到这些错误，但是它不起作用

    process = new Process();
    process.StartInfo.RedirectStandardOutput = true;
    process.StartInfo.RedirectStandardError = true;
    process.OutputDataReceived += new DataReceivedEventHandler(OutputHandlerData);
    process.ErrorDataReceived += new DataReceivedEventHandler(OutputHandlerError);
    process.StartInfo.UseShellExecute = false;
    process.StartInfo.CreateNoWindow = true;
    process.StartInfo.FileName = "test.bat";
    process.Start();
    process.BeginOutputReadLine();
    process.BeginErrorReadLine();

    private void OutputHandlerError(object sendingProcess, DataReceivedEventArgs outLine)
    {
        log = log + outLine.Data + "\n";
        WriteInLog(log);
    }

        private void OutputHandlerData(object sendingProcess, DataReceivedEventArgs outLine)
    {
        if (outLine.Data != null)
        {
            if (outLine.Data.Contains("can not find"))
            {
                log = log + outLine.Data;
                WriteInLog(log);
            }
        }
    }

Answer 1

最后，我更改了MSBuild命令的详细说明，现在我可以输出带有OutputDataReceived事件的所有句子，而不会阻止应用程序，因为它显示的信息少得多。我还保存了一个文件，其中包含有关编译的更多信息。

MSBuild.exe -v:q -clp:ErrorsOnly;NoSummary -fl -flp:logfile=MyProjectOutput.log;verbosity=normal ..\MySolution.sln

-v：q-> verbose = quiet
-clp：ErrorsOnly; NoSummary->仅显示错误
-fl -flp：logfile = MyProjectOutput.log; verbosity = normal->创建一个名为MyProjectOutput.log的文件以保存verbosity = normal的日志（显示错误，警告，高重要性消息，正常重要性消息）

如何获取由进程启动的Msbuild错误？

1 个答案: