Question

我试图验证该行是否有到达日期，那么我的函数应该进行计算，否则什么也不做。如您在图片中看到的，第一行具有所有值，并且LOS时间正确，但是其他行没有值，并且LOS应该为空。

这是我的型号代码：

function time_ago($ptime) {

    $query = null; //emptying in case 
    $shift_id   = $_POST['shift_id'];
    $arrival_time = $_POST['arrival_time'];
    $query = $this->db->get_where('shift', array('shift_id' => $shift_id));
    $count = $query->num_rows(); //counting result from query       

    if ($count = 0) {

    $today = time();
    $createdday = strtotime($ptime); //mysql timestamp of when post was created 

    $datediff = abs($today - $createdday);
    $difftext = "";
    $years = floor($datediff / (365 * 60 * 60 * 24));
    $months = floor(($datediff - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
    $days = floor(($datediff - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 * 24) / (60 * 60 * 24));
    $hours = floor($datediff / 3600);
    $minutes = floor($datediff / 60);
    $seconds = floor($datediff);
    //year checker  
    if ($difftext == "") {
        if ($years > 1)
            $difftext = $years . " years";
        elseif ($years == 1)
            $difftext = $years . " year";
    }
    //month checker  
    if ($difftext == "") {
        if ($months > 1)
            $difftext = $months . " months";
        elseif ($months == 1)
            $difftext = $months . " month";
    }
    //month checker  
    if ($difftext == "") {
        if ($days > 1)
            $difftext = $days . " days";
        elseif ($days == 1)
            $difftext = $days . " day";
    }
    //hour checker  
    if ($difftext == "") {
        if ($hours > 1)
            $difftext = $hours . " hours";
        elseif ($hours == 1)
            $difftext = $hours . " hour";
    }
    //minutes checker  
    if ($difftext == "") {
        if ($minutes > 1)
            $difftext = $minutes . " minutes";
        elseif ($minutes == 1)
            $difftext = $minutes . " minute";
    }
    //seconds checker  
    if ($difftext == "") {
        if ($seconds > 1)
            $difftext = $seconds . " seconds";
        elseif ($seconds == 1)
            $difftext = $seconds . " second";
    }
    return $difftext;
}else{
return null; 
}
 }

Answer 1

您可以向函数添加新条件，而不是SQL检查您的函数将如下所示：

    function time_ago($ptime) {
    $today = time();
    $createdday = strtotime($ptime); //mysql timestamp of when post was created     
    $datediff = abs($today - $createdday);
    $difftext = "";
    $years = floor($datediff / (365 * 60 * 60 * 24));
    $months = floor(($datediff - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
    $days = floor(($datediff - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 * 24) / (60 * 60 * 24));
    $hours = floor($datediff / 3600);
    $minutes = floor($datediff / 60);
    $seconds = floor($datediff);
    //year checker  
    if ($difftext == "") {
        if ($years > 1)
            $difftext = $years . " years";
        elseif ($years == 1)
            $difftext = $years . " year";
    }
    //month checker  
    if ($difftext == "") {
        if ($months > 1)
            $difftext = $months . " months";
        elseif ($months == 1)
            $difftext = $months . " month";
    }
    //month checker  
    if ($difftext == "") {
        if ($days > 1)
            $difftext = $days . " days";
        elseif ($days == 1)
            $difftext = $days . " day";
    }
    //hour checker  
    if ($difftext == "") {
        if ($hours > 1)
            $difftext = $hours . " hours";
        elseif ($hours == 1)
            $difftext = $hours . " hour";
    }
    //minutes checker  
    if ($difftext == "") {
        if ($minutes > 1)
            $difftext = $minutes . " minutes";
        elseif ($minutes == 1)
            $difftext = $minutes . " minute";
    }
    //seconds checker  
    if ($difftext == "") {
        if ($seconds > 1)
            $difftext = $seconds . " seconds";
        elseif ($seconds == 1)
            $difftext = $seconds . " second";
    }
    if ($difftext == "49 years") {
            $difftext = "";
    }
    return $difftext;
}

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