Question

我有以下PowerShell代码：

[xml]$xml = Get-Content uccxResourceList_forReference.xml
$xml.resources.resource |
    Select-Object firstname, lastname, extension,
        @{Name="Team"; Expression={($_.team.name)}} | 
    Sort Team |
    Format-Table

生成如下表：

firstName   lastName    extension   Team
---------   --------    ---------   ----------------
Homer       Simpson     1000        SafetyInspectors
Frank       Grimes      1001        SafetyInspectors
Lenford     Leonard     1002        SafetyInspectors
Carlton     Carlson     1003        SafetyInspectors
Montgomery  Burns       2000        Executives
Waylon      Smithers    2001        Executives

我想做的是将每个团队输出到自己的文件中。因此，不只是最后一个简单的| Out-File teamlist.txt，而是我想输出一个文本文件，其中包含所有“ SafetyInspectors”和另一个包含所有“ Executives”的文件。

我知道我可以通过随后的foreach循环来完成此操作，但是我认为它也可以在管道中完成，而我只是不知道该怎么做。

Answer 1

我希望输出到一个csv文件（可以轻松地再次导入），所以：

[xml]$xml = Get-Content uccxResourceList_forReference.xml
$xml.resources.resource |
    Select-Object firstname, lastname, extension,
        @{Name="Team"; Expression={($_.team.name)}} | 
      Group-Object Team | ForEach-Object {
         $_.Group | Export-Csv ("{0}.csv" -f $_.Name) -NoTypeInformation
      }

应返回如下内容：

> gc .\Executives.csv
"firstName","lastName","extension","Team"
"Montgomery","Burns","2000","Executives"
"Waylon","Smithers","2001","Executives"

> gc .\SafetyInspectors.csv
"firstName","lastName","extension","Team"
"Homer","Simpson","1000","SafetyInspectors"
"Frank","Grimes","1001","SafetyInspectors"
"Lenford","Leonard","1002","SafetyInspectors"
"Carlton","Carlson","1003","SafetyInspectors"

将排序数据的排序部分输出到变量？

1 个答案: