Question

ORA-06550：第4行，第3列 PLS-00905：对象HR.procempno无效

-我已经尝试过此代码-

create or replace procedure procempno(p_no in number)
IS
  v_salary number(10,2);
begin
  v_salary:=(select salary from emp where employee_id=p_no);
if v_salary>1000 then
  update emp set salary=v_salary*1.75;
else 
  update emp set salary=5000;
end if;
Exception when no_data_found then
  dbms_output.put_line(p_empno||' doesnt exists');
end procempno;

-以下是我最近的代码-

create or replace procedure procempno(p_no in number)
IS
v_salary number(10,2);
begin
  select salary into v_salary from emp where employee_id=p_no;
  if v_salary>1000 then
    update emp set salary=v_salary*1.75 where employee_id=p_no;
  else 
    update emp set salary=5000 where employee_id=p_no;
  end if;
Exception when no_data_found then
  dbms_output.put_line(p_empno||' doesnt exists');
end procempno;

-使用PLSQL块执行-

declare 
  v_empno number;
begin
  procempno(&v_empno);
end;

让我们考虑一下，empno = 100的工资为25000。如果输入empno = 100，则检查条件是否为25000> 1000（如果是），则更新薪水=薪水* 1.75。否则更新工资= 5000

Answer 1

您在第

行有输入错误

dbms_output.put_line(p_empno||' doesnt exists');

您应该使用 p_no

dbms_output.put_line(p_no||' doesnt exists');

不要忘记 COMMIT ，并使用良好的代码标准

CREATE OR REPLACE PROCEDURE procempno(p_no IN emp.employee_id%TYPE) IS
  v_salary emp.salary%TYPE;
BEGIN
  SELECT salary
    INTO v_salary
    FROM emp
   WHERE employee_id = p_no;

  IF v_salary > 1000
  THEN
    UPDATE emp
       SET salary = v_salary * 1.75
     WHERE employee_id = p_no;
  ELSE
    UPDATE emp
       SET salary = 5000
     WHERE employee_id = p_no;
  END IF;

  COMMIT;
EXCEPTION
  WHEN NO_DATA_FOUND THEN
    dbms_output.put_line(p_no || ' doesnt exists');
END procempno;

Answer 2

您可以避免将当前薪水选择到局部变量中并直接更新。对于更漂亮的输出，我确实声明了private func loadUniversity(url: String) { let configuration = URLSessionConfiguration.ephemeral let session = URLSession(configuration: configuration) let url = URL(string: url)! let task = session.dataTask(with: url) { (data, response, error) in guard let httpResponse = response as? HTTPURLResponse, httpResponse.statusCode == 200, let data = data else { return } do { let decoder = JSONDecoder() let university = try decoder.decode([UniversityJSON].self, from: data) for item in university { self.universityArray.append(University(name: item.university_name.trim())) } let queue = OperationQueue.main queue.addOperation { self.currentUniversityArray = self.universityArray print(self.currentUniversityArray) self.table.reloadData() } } catch { print("Error info: \(error)") } } task.resume() } func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell { guard let cell = tableView.dequeueReusableCell(withIdentifier: "Cell") as? UniversityCell else { return UITableViewCell() } cell.name.text = currentUniversityArray[indexPath.row].name return cell }，它将用于显示新的薪水。

这里是一个示例：首先，我将基于Scott的EMP表创建一个临时表（看起来像您的表）：

RETVAL

过程：有用的部分是第5-9行，它们可以完成您想要的操作。其余的不必要。在第12-16行中，我正在检查是否进行了任何更新（例如，拥有SQL> create table t_emp as 2 select empno as employee_id, 3 sal as salary 4 from emp; Table created.的员工存在-请注意，在这种情况下，我不需要P_NO的异常处理程序）。

NO_DATA_FOUND

测试：

SQL> create or replace procedure procempno (p_no in number)
  2  is
  3    retval t_emp.salary%type;
  4  begin
  5    update t_emp e set
  6      e.salary = case when e.salary > 1000 then e.salary * 1.75
  7                      else 5000
  8                 end
  9      where e.employee_id = p_no
 10      returning e.salary into retval;
 11
 12    if sql%rowcount = 0 then
 13       dbms_output.put_line(p_no || ' does not exist');
 14    else
 15       dbms_output.put_line('Salary updated to ' || retval);
 16    end if;
 17  end;
 18  /

Procedure created.

SQL>

将employeeno用作过程的参数并修改该员工的薪水？

2 个答案: