Question

我的目标是，domain.com/do/that/的调用将包含页面otherdomain.com/for/that/，并用ssi＆subs过滤器替换该内容的一部分。同样，重要的是，如果有人致电domain.com/do/that/for-me，则包含的页面将只请求otherdomain.com/for/that，而不 otherdomain.com/for/that/for-me。

我目前已对此进行设置：

location ^~/do/that/ {
  proxy_pass http://otherdomain.com/do/that/;

  ssi on;
  subs_filter_types text/html;

  set $includeUri "";
  if ( $uri != "/do/that/" ){
    set $includeUri "$uri-parts";
  }

 subs_filter '<div class="rpl-container">' '<div class="rpl-container"><!--# include virtual="/my-ssi-include/$includeUri" -->' ir;
}

实现uri的“忽略”的方式是什么？

Answer 1

已经找到解决方案：

我只是将var与静态网址一起使用，并将其设置为proxy_pass

location ^~/do/that/ {
  set $staticUrl 'http://otherdomain.com/do/that/';
  proxy_pass $staticUrl;

  ssi on;
  subs_filter_types text/html;

  if ($uri ~* "/do/that/(.*\.html)"){
    set $includeUri "$1";
  }

 subs_filter '<div class="rpl-container">' '<div class="rpl-container"><!--# include virtual="/my-ssi-include/$includeUri" -->' ir;
}

nginx proxy_pass不通过uri

1 个答案: