Question

我一直在疯狂地尝试解决并解决此问题。我用赌注证明了这个骰子滚动游戏。我对编码非常陌生，因此可以肯定，这是一个我一直忽略的简单错误。

唯一的问题是，如果用户输入“否”，它将不会结束游戏。
- 该函数不返回任何错误。它会运行并甚至打印GAME OVER，然后返回用于确定玩家是否想再玩一轮的值。
发生的事情是先将游戏打印出来，然后循环diceRoll函数而不停止它。

上传图片以显示我的意思。 enter image description here

和代码：

#pylint:disable=W0312
#python 3.6
from random import randint
import math

# Static Variables
START_BALANCE = 2500

# Game messages
BAD_GUESS = "ERROR! You can only enter a number between 1 and 6.\n- Your input was '{}'.\n"
BAD_BET = "ERROR! You can not bet less than 0 or more than your current balance {}$.\n"
userName = input("What is your name, player?\n").title()

print("Hello, {}! Welcome to the dice rolling game v.2!\n".format(userName))

def get_guess():
    try:
        guess = input("Enter a guess from 1 to 6, {}\n".format(userName))
        guess = int(guess)
        while (guess <= 0 or guess > 6):
            print(BAD_GUESS.format(guess))
            return get_guess()

    except ValueError:
        print(BAD_GUESS.format(guess))
        return get_guess()

    else:
            print("Your guess is: {}.".format(guess))
            return guess

def get_bet(balance):
    try:
        bet = input("\nHow much do you want to bet? Your balance is: {}$\n".format(balance))
        bet = int(bet)
        while (balance < bet) or (bet < 0):
            print(BAD_BET.format(balance))
            return get_bet(balance)

    except ValueError:
        print(BAD_BET.format(balance))
        return get_bet(balance)

    else:
        print("You have bet {}$!\n- Your remaining balance is: {}$".format(bet, balance - bet))
        return bet

#### FUNC START ####

def diceRoll(balance): 
    bet = get_bet(balance)
    guess = get_guess()
    balance -= bet
    roll = randint(1,6)

    if (roll == guess):
        prize = bet * float(3.75)
        prize = math.ceil(prize)
        balance += prize

        print("\nYOU WIN {}$!".format(prize))
        print("You guessed: {} - The roll was {}!\n".format(guess, roll))
        print("-- Your balance is now {}$ -- \n".format(balance))

    elif (roll != guess):
        print("\nYOU LOSE {}$".format(bet))
        print("The roll was: {} - You guessed: {}.".format(roll,guess))
        print("-- Your balance is now {}$ --\n".format(balance))
        #
        choice = input("Would you like to try again?  Y/N\n").upper()
        # 
    if (balance <= 0 or choice == "YES" or  "Y"):
        print("New round! Your balance is {}$".format(balance))
        return [True, balance]
    else:
        print("GAME OVER! \n Balance: {}$".format(balance))
        return [False, balance]


# Initialize game_state, which is a variable that keeps track of your rounds and balance.
game_state = [True, START_BALANCE]

# game_state[0] contains True if the user wants to play again, False if not.
# So if it's false, while (game_state[0]) will evaluate to false and stop the while loop.
while game_state[0]:
    game_state = diceRoll(game_state[1])

# TODO: Build a while loop that executes any time the first item in game_state is True (i.e., while the
# user still wants to play a new round. Note that I initialized game_state[0] to True, assuming that 
# if they started the program, they want to play the first round.

Answer 1

在diceRoll()函数内部，应更改为：

if (balance <= 0 or choice == "YES" or  "Y")

到

if (balance <= 0 or choice == "YES" or choice == "Y")

正确地与choice值进行比较。

为清楚起见，您有3种情况：

balance <= 0
choice == "YES"
"Y"

，第三个总是True。它不会检查choice是否具有Y的值，但是会检查您提供的"Y"是否等于None的字符串，并且显然不是，因此始终为True。

Answer 2

除了给出的答案外，我还建议列出肯定选择字符串，并检查其中是否包含choice。

acceptables = ["yes", "y", "yup", "yeah", "sure", "absolutely", "1", "roger"]

if (balance <= 0 or choice.lower() in acceptables)

.lower()将输入字符串转换为小写，因此您不必为此而烦恼。如果您不希望在上述情况下提供更多示例，则可以随时添加它们。相同于“不”，“不”，“不行”，“从不”，“ 0”，...

While循环不会结束功能

2 个答案: