我有一个表company_basics
,其中有parent_id
,这种子对父母的关系可以不受限制。
当前,我的代码是
$company = \App\CompanyBasic::whereRaw('user_id = ' . Auth::user()->id . " AND parent_id = 0")->get();
// echo "<pre>";
// print_r($company);
// echo "</pre>";
$companies = array();
$count = 0;
foreach($company as $single_company) {
$companies[$count]['id'] = $single_company->id;
$companies[$count]['comp_name'] = $single_company->comp_name;
$child_company = \App\CompanyBasic::whereRaw('user_id = ' . Auth::user()->id . " AND parent_id = '" . $single_company->id . "'")->get();
$child_count = 0;
foreach($child_company as $single_child_company) {
$companies[$count]['child'][$child_count]['id'] = $single_child_company->id;
$companies[$count]['child'][$child_count]['comp_name'] = $single_child_company->comp_name;
$child_count++;
}
echo "company id: " . $single_company->id . "<br>";
$count++;
}
我只能让父母陪伴,并通过他们寻找孩子,但这是一个级别的下调,但我想无限地向下移动。
现在返回的代码是
Array
(
[0] => Array
(
[id] => 2
[comp_name] => Habib company
[child] => Array
(
[0] => Array
(
[id] => 16
[comp_name] => Child Company
)
[1] => Array
(
[id] => 18
[comp_name] => Child Company
)
)
)
[1] => Array
(
[id] => 15
[comp_name] => Adjacent Company
)
[2] => Array
(
[id] => 17
[comp_name] => MSB34
)
)
答案 0 :(得分:2)
按照@rypskar的建议,您应该使用递归。
我建议您使用anonymous function并将其内部使用(称为closure
),并执行以下操作:
$userId = Auth::user()->id;
$getChildOf = function ($parent) use ($userId, &$getChildOf) {
$company = \App\CompanyBasic::whereRaw('user_id = ' . $userId . " AND parent_id = " . $parent)->get();
$companies = false;
if ($company->isNotEmpty()) {
$companies = array();
foreach ($company as $single_company) {
$companies[] = array(
'id' => $single_company->id,
'comp_name' => $single_company->comp_name,
'child' => $getChildOf($single_company->id),
);
echo "company id: " . $single_company->id . "<br>";
}
}
return $companies;
};
$companies = $getChildOf(0);
这里,匿名函数传递给变量$getChildOf
,该变量用于自身。
我已删除您的$count
变量以简化代码。
顺便说一句,您应该了解该代码将在每次迭代时执行数据库查询,因此将大大增加服务器负载
此外,通过串联向SQL查询中注入变量是不安全的,并且被认为是不好的做法。您应该考虑使用prepared statements