Question

我目前正在尝试构建一个非常简单的程序，在该程序中，要求用户选择路径，并根据所选择的路径来更新词典。看来，当用户首先选择path_2b时，它会继续运行并打印“恭喜完成游戏”并停止运行，即使仅在字典中添加了path_2b时，它也才停止运行，而只有在同时存在两个路径时，它才应停止运行。开始一般地学习Python和编程的知识，因此感谢您的帮助和提示！

user_save = {}

def start_button():
    def path_2a():
        if "path_1" in user_save:
            print("You've already taken this path.")
        else:
            user_save["path_1"] = "completed"
            print("Congrats on finishing this path!")
    def path_2b():
        if "path_2" in user_save:
            print("You've alredy taken this path.")
        else:
            user_save["path_2"] = "Completed"
            print("Congrats on finishing this path!")

    chosen_path = input("Would you like to choose path 2A or 2B?: ").lower()
    if chosen_path == "2a":
        path_2a()
    elif chosen_path == "2b":
        path_2b()
    else:
        print("Sorry that isn't a valid path. Please try again.")

while ("path_1" and "path_2") not in user_save:
    start_button()
if "path_1" and "path_2" in user_save:
    print("Congrats on finishing the game!")

我希望循环一直运行，直到用户选择了路径1和2。一旦这两个键都在字典中，我想打印一个祝贺消息并中断循环。就像我在大多数代码运行正常之前所说的那样。如果用户首先选择path_2a，然后选择2b，则即使他们选择的路径不存在，循环也将按照我想要的方式进行操作。仅当用户首先选择path_2b时。感谢您的帮助！

Answer 1

代替将函数放入函数中，请尝试以下操作。我已简化为使用“ 2a”和“ 2b”作为实际的键名。另外，由于2a和2b都确定您要退出的时间，因此可以跳过while循环，而只使用一个在选择2a和2b后退出的函数，否则将继续运行。

def play_game(user_save):
    chosen_path = input("Would you like to choose path 2A or 2B?: ").lower()

    if chosen_path not in ['2a', '2b']:
        print("Sorry that isn't a valid path. Please try again.")
    elif chosen_path in user_save:
        print("You've already taken this path.")
    else:
        user_save[chosen_path] = "Completed"
        print("Congrats on finishing this path!")

    # If both 2a and 2b have been taken, just "return" to exit.
    if '2a' in user_save and '2b' in user_save:
        print("Congrats on finishing the game!")
        return

    # If they're still here, loop it again. Take the updated
    # dictionary <user_save> as input for the next round.
    play_game(user_save)


# Run the program
user_save = {}
play_game(user_save)

Answer 2

根据您的代码，您需要更改代码：

user_save = {}

def start_button():
    def path_2a():
        if "path_1" in user_save:
            print("You've already taken this path.")
        else:
            user_save["path_1"] = "completed"
            print("Congrats on finishing this path!")
    def path_2b():
        if "path_2" in user_save:
            print("You've alredy taken this path.")
        else:
            user_save["path_2"] = "Completed"
            print("Congrats on finishing this path!")

    chosen_path = input("Would you like to choose path 2A or 2B?: ").lower()
    if chosen_path == "2a":
        path_2a()
    elif chosen_path == "2b":
        path_2b()
    else:
        print("Sorry that isn't a valid path. Please try again.")

while  "path_2" not in user_save or "path_1" not in user_save:
    start_button()

if "path_2" in user_save and "path_1" in user_save:
    print("Congrats on finishing the game!")

如果键不在字典中，则运行while循环

2 个答案: