Question

我有3张桌子：

表1：表名称：FULL_DATA

DATE        ORDER_NO               AMOUNT   MODE
01-04-2019  ADVANVCE.:ORD1971718    5000    DEBIT-CARD
01-04-2019  ADVANVCE.:ORD1961718    6000    CASH
01-04-2019  ADVANVCE.:ORD2001819    8000    CASH
02-04-2019  ADVANVCE.:ORD2011819    10000   CASH
02-04-2019  ADVANVCE.:ORD0891819    3000    CASH
02-04-2019  ADVANVCE.:ORD2021819    8000    DEBIT-CARD
02-04-2019  ADVANVCE.:ORD2031819    12000   CASH
03-04-2019  ADVANVCE.:ORD2041819    14000   CASH
03-04-2019  ADVANVCE.:ORD2051819 17000  CASH
03-04-2019  ADVANVCE.:ORD2061819    14000   CASH
03-04-2019  ADVANVCE.:ORD2061819    15000   DEBIT-CARD
03-04-2019  ADVANVCE.:ORD2071819    4000    DEBIT-CARD
03-04-2019  ADVANVCE.:ORD2071819    1000    CASH
04-04-2019  ADVANVCE.:ORD2101819    500 CASH
04-04-2019  ADVANVCE.:ORD2091819    1000    CASH
04-04-2019  ADVANVCE.:ORD2081819    2000    CASH
04-04-2019  ADVANVCE.:ORD0471819    8000    CASH

表2：表名称：ORDER_DETAILS

ORDER_NO    ITEM_NAME   CUSTOMER_ID
ORD2001819  ITEM-1      7
ORD2011819  ITEM-2      6
ORD2021819  ITEM-3      5
ORD2021819  ITEM-4      5
ORD2021819  ITEM-5      5
ORD2021819  ITEM-6      5
ORD2031819  ITEM-7      8
ORD2041819  ITEM-8      67
ORD2041819  ITEM-9      67
ORD2051819  ITEM-10     89
ORD2061819  ITEM-11     54
ORD2061819  ITEM-12     54
ORD2071819  ITEM-13     11
ORD2101819  ITEM-14     12
ORD2091819  ITEM-15     14
ORD2081819  ITEM-16     16
ORD1971718  ITEM-17     68
ORD1971718  ITEM-18     68
ORD0471819  ITEM-19     90
ORD0891819  ITEM-20     44
ORD1961718  ITEM-21     55

表3：表名称：CUSTOMER_DETAILS

CUSTOMER_ID    CUSTOMER_NAME
7              CUSTOMER-1
6              CUSTOMER-24
5              CUSTOMER-39
8              CUSTOMER-40
67             CUSTOMER-15
89             CUSTOMER-66
54             CUSTOMER-7
11             CUSTOMER-89
12             CUSTOMER-9
14             CUSTOMER-10
16             CUSTOMER-11
68             CUSTOMER-121
90             CUSTOMER-134
44             CUSTOMER-147
55             CUSTOMER-158

查询JOIN的这些表，它们将从FULL_DATA表中获取日期，ORDER_NO，数量，模式列以及JOIN的ORDER_NO（通过使用ORDER_DETAILS表将订单号分割成“：”来获取订单号）并获取它的客户ID，然后JOIN及其客户ID与客户详细信息表并获取客户名称？???

看起来像这样的数据：

最终查询结果：

DATE        CUSTOMER_NAME   ORDER_NO               AMOUNT   MODE
01-04-2019  CUSTOMER-121    ADVANVCE.:ORD1971718    5000    DEBIT-CARD
01-04-2019  CUSTOMER-158    ADVANVCE.:ORD1961718    6000    CASH
01-04-2019  CUSTOMER-1      ADVANVCE.:ORD2001819    8000    CASH
02-04-2019  CUSTOMER-24     ADVANVCE.:ORD2011819    10000   CASH
02-04-2019  CUSTOMER-147    ADVANVCE.:ORD0891819    3000    CASH
02-04-2019  CUSTOMER-39     ADVANVCE.:ORD2021819    8000    DEBIT-CARD
02-04-2019  CUSTOMER-40     ADVANVCE.:ORD2031819    12000   CASH
03-04-2019  CUSTOMER-15     ADVANVCE.:ORD2041819    14000   CASH
03-04-2019  CUSTOMER-66     ADVANVCE.:ORD2051819    17000   CASH
03-04-2019  CUSTOMER-7      ADVANVCE.:ORD2061819    14000   CASH
03-04-2019  CUSTOMER-7      ADVANVCE.:ORD2061819    15000   DEBIT-CARD
03-04-2019  CUSTOMER-89     ADVANVCE.:ORD2071819    4000    DEBIT-CARD
03-04-2019  CUSTOMER-89     ADVANVCE.:ORD2071819    1000    CASH
04-04-2019  CUSTOMER-9      ADVANVCE.:ORD2101819    500     CASH
04-04-2019  CUSTOMER-10     ADVANVCE.:ORD2091819    1000    CASH
04-04-2019  CUSTOMER-11     ADVANVCE.:ORD2081819    2000    CASH
04-04-2019  CUSTOMER-134    ADVANVCE.:ORD0471819    8000    CASH

Answer 1

如果数据中的订单号始终是:之后的最后一部分？

SELECT
 d.DATE, 
 GROUP_CONCAT(DISTINCT c.CUSTOMER_NAME) AS CUSTOMER_NAMES,
 d.ORDER_NO,
 d.AMOUNT,
 d.MODE
FROM FULL_DATA d
LEFT JOIN ORDER_DETAILS o 
  ON o.ORDER_NO = RTRIM(SUBSTRING_INDEX(d.ORDER_NO,':',-1))
LEFT JOIN CUSTOMER_DETAILS c ON c.CUSTOMER_ID = o.CUSTOMER_ID
GROUP BY 
 d.DATE, 
 d.ORDER_NO,
 d.AMOUNT,
 d.MODE

每个订单有多个商品。
从理论上讲，每个订单可能有1个以上的客户。
因此，此处使用GROUP_CONCAT而不是MAX。

Answer 2

它将从full_data表中获取每个订单号，并使用第二和第三表查找没有订单的客户详细信息，并在日期列后显示我的客户名称

Answer 3

我通过从order_detaisl为customer_id和order_no选择不同的值进行了加入

SELECT f.DATE, CUSTOMER_NAME, f.ORDER_NO, AMOUNT, MODE 
FROM FULL_DATA f
JOIN (SELECT DISTINCT customer_id, order_no 
      FROM ORDER_DETAILS) o ON SUBSTRING_INDEX(f.ORDER_NO,':',-1)= o.ORDER_NO 
JOIN CUSTOMER_DETAILS c ON o.CUSTOMER_ID = c.CUSTOMER_ID 
WHERE f.DATE BETWEEN '2019-04-01' AND '2019-04-04' 
ORDER BY f.DATE ASC

MySQL查询联接三个表并从第二和第三表获取数据

3 个答案: