Task.WaitAll上的System.AggregateException

时间:2019-01-13 15:17:57

标签: c# task aggregateexception

我有以下代码可以触发多个异步任务。

        List<TimeoutException> TimeoutExceptions = new List<TimeoutException>();
        List<TaskCanceledException> TaskCanceledExceptions = new List<TaskCanceledException>();
        List<Exception> Exceptions = new List<Exception>();
        List<AggregateException> AggregateExceptions = new List<AggregateException>();

        List<Models.Channel.IChannel> channels = new List<Models.Channel.IChannel>();            
        channels.Add(new Models.Channel.DummyChannelName());            

        var tasks = new List<Task>();
        foreach (Models.Channel.IChannel channel in channels)
        {
            try
            {
                var cts = new CancellationTokenSource();                    
                cts.CancelAfter(channel.TimeOut);

                tasks.Add(Task.Run(() =>
                { 
                    channel.Data = channel.RequestOffers(new Models.Request.AvailabilityRequest()).Result;

                    if (cts.Token.IsCancellationRequested)                        
                        cts.Token.ThrowIfCancellationRequested();

                }, cts.Token));
            }
            catch (TimeoutException t)
            {
                TimeoutExceptions.Add(t);
            }
            catch (TaskCanceledException tc)
            {
                TaskCanceledExceptions.Add(tc);
            }
            catch (AggregateException ae)
            {
                AggregateExceptions.Add(ae);
            }
            catch(Exception ex)
            {
                Exceptions.Add(ex);
            }

        }

        Task.WaitAll(tasks.ToArray(), TimeSpan.FromSeconds(5));

我遇到的问题是,如果由于超时而取消任务,我将收到以下异常

<ExceptionMessage>One or more errors occurred.</ExceptionMessage>
<ExceptionType>System.AggregateException</ExceptionType>

是否只是一个简单的案例,我需要围绕Task.WaitAll进行Try Catch,还是应该以不同的方式构造我的代码?

1 个答案:

答案 0 :(得分:1)

如果任务内发生异常,则Wait会在任务上在调用线程上引发异常。如果成功创建了任务,则该任务内部发生的所有异常都将被封装在AggregateException中并等待。

以您为例,这意味着您可以在循环中删除try / catch块,并在循环后使用它包装Task.WaitAll(...)

var tasks = new List<Task>();
foreach (Models.Channel.IChannel channel in channels)
{
    Task myTask = Task.Run(...); // create your task here
    tasks.Add(myTask);
}

try
{
    Task.WaitAll(tasks.ToArray(), TimeSpan.FromSeconds(5));
}
catch
{
    // Insert Exception handling logic
}