我试图解决Leetcode问题54-螺旋 并卡在空向量输入中。
问题在于螺旋清单。输入为2d向量,输出应为螺旋方向写入的向量列表。
public class ConnectionClass {
String ip = "public_address"; //works with local 192.168.100.4
String classs = "net.sourceforge.jtds.jdbc.Driver";
String db = "ProiectBD"; //baza de date
String un = "proiectbd1"; //username
String password = "123"; //password
@SuppressLint("NewApi")
public Connection CONN() {
StrictMode.ThreadPolicy policy=new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
Connection conn = null;
String ConnURL = null;
try {
Class.forName(classs);
ConnURL = "jdbc:jtds:sqlserver://" + ip + ";"
+ "databaseName=" + db + ";user=" + un + ";password="
+ password + ";";
conn = DriverManager.getConnection(ConnURL);
} catch (SQLException se) {
Log.e("ERRO", se.getMessage());
} catch (ClassNotFoundException e) {
Log.e("ERRO", e.getMessage());
} catch (Exception e) {
Log.e("ERRO", e.getMessage());
}
return conn;
}}
问题是输入为空列表时。
Input:
[
[1, 2, 3, 4],
[5, 6, 7, 8],
[9,10,11,12]
]
Output: [1,2,3,4,8,12,11,10,9,5,6,7]
它会产生运行时错误。
通过了另一个测试用例,除了 [] 之类的空输入。
在我的Mac OSX终端中进行测试时似乎没有运行时错误, 但是Leetcode说
'行933:字符34:运行时错误:引用绑定到类型为'struct value_type'(stl_vector.h)的空指针 '
这里是链接 https://leetcode.com/problems/spiral-matrix/
我还在下面附加代码...
Input: []
答案 0 :(得分:1)
感谢您的评论,我想出了解决自己的方法。 我改变了
if(matrix[0].size()<1
到
if(matrix.empty()) return {};
成功了。 我也发现我的算法是错误的,并对其进行了修复。
using namespace std;
enum class Direction{
RIGHT,
DOWN,
LEFT,
UP
};
class Solution {
public:
Direction direc;
vector<int> answer;
int left = 0, right = 0;
vector<int> spiralOrder(vector<vector<int>>& matrix) {
Direction direc = Direction::RIGHT;
if(matrix.empty()) return {};
vector<vector<int>> flag(matrix.size(),vector<int>(matrix[0].size(),0));
while(1){
flag[left][right] =1;
answer.push_back(matrix[left][right]);
switch(direc){
case Direction::RIGHT:
if(right+1<matrix[0].size() && flag[left][right+1] == 0){
++right;
continue;
}
else if(left+1<matrix.size() && flag[left+1][right] == 0 ){
++left;
direc = Direction::DOWN;
continue;
}
else break;
case Direction::DOWN:
if(left+1<matrix.size() && flag[left+1][right] == 0 ){
++left;
continue;
}
else if(right-1>=0 && flag[left][right-1]==0){
--right;
direc = Direction::LEFT;
continue;
}
else break;
case Direction::LEFT:
if(right-1>=0 && flag[left][right-1]==0){
--right;
continue;
}
else if(left-1>=0 && flag[left-1][right]==0){
--left;
direc = Direction::UP;
continue;
}
else break;
case Direction::UP:
if(left-1>=0 && flag[left-1][right]==0){
--left;
continue;
}
else if(right+1<matrix[0].size() && flag[left][right+1] == 0){
++right;
direc = Direction::RIGHT;
continue;
}
else break;
}
break;
} // switch-case
return answer;
}
};
答案 1 :(得分:0)
@package
意味着您只能检查向量是否为空并立即返回。您不能做其他事情,例如声明变量。如果在检查空向量之前确实进行了其他操作,则会收到上述警告。
Line 923: Char 9: runtime error: reference binding to null pointer of type 'std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> >' (stl_vector.h)