如果我仅使用一个类,则效果很好,但是当我使用多个类时,我面临一个问题,其中,当我将输入全部作为批处理(复制粘贴)时,它不起作用(仍然等待更多输入,但什么也不做),但是当我手动输入每个输入时,效果很好。
所以,这个问题是在我引入一个新类时开始的,所以我猜想在与Scanner类一起使用时,该类或继承有问题。
请比较一下,让我知道错误
注意:这是给我的大学实验室用的,所以我不能在这里使用文件。
btw,MyInputs是
5
5 0
2 9 -10 25 1
5 1
2 9 -10 25 1
5 1
2 9 -10 25 1
5 0
2 9 -10 25 1
5 1
2 9 -10 25 1
预期产量
5.400000
4.000000
4.000000
5.400000
4.000000
codeWithSingleClass-完美的作品
import java.io.*;
import java.lang.*;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner=new Scanner(System.in);
int nooftestCases=scanner.nextInt();
while(nooftestCases>0) {
int n,k;
int[] array = new int[20];
int sumWithOutRemoval=0 , sumWithRemoval=0;
n = scanner.nextInt();
k = scanner.nextInt();
sumWithOutRemoval = 0;
for (int i = 0; i < n; i++) {
array[i] = scanner.nextInt();
sumWithOutRemoval += array[i];
}
if (k == 0) {
double finalAns = (double) sumWithOutRemoval / n;
System.out.println(String.format("%.6f", finalAns));
} else {
for (int i = 0; i < n; i++) {
for (int j = i; j < n; j++) {
if (array[i] < array[j]) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
}
sumWithRemoval = 0;
for (int i = 1; i < n - 1; i++) {
sumWithRemoval += array[i];
}
double finalAns = (double) (sumWithRemoval / (n - (2 * k)));
System.out.println(String.format("%.6f", finalAns));
}
nooftestCases--;
}
}
}
--->codeWithMultipleClasses-hasIssues<----
import java.io.*;
import java.lang.*;
import java.util.Scanner;
class Sample {
static int n,k;
static int[] array = new int[20];
static int sumWithOutRemoval , sumWithRemoval;
public void getDetails(){
Scanner scanner2=new Scanner(System.in);
n = scanner2.nextInt();
k = scanner2.nextInt();
sumWithOutRemoval = 0;
for (int i = 0; i < n; i++) {
array[i] = scanner2.nextInt();
sumWithOutRemoval += array[i];
}
}
public void displayDetails(){
if (k == 0) {
double finalAns = (double) sumWithOutRemoval / n;
System.out.println(String.format("%.6f", finalAns));
}
else {
for (int i = 0; i < n; i++) {
for (int j = i; j < n; j++) {
if (array[i] < array[j]) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
}
sumWithRemoval = 0;
for (int i = 1; i < n - 1; i++) {
sumWithRemoval += array[i];
}
double finalAns = (double) (sumWithRemoval / (n - (2 * k)));
System.out.println(String.format("%.6f", finalAns));
}
}
}
public class Main extends Sample {
public static void main(String[] args) {
Scanner scanner=new Scanner(System.in);
int nooftestCases=scanner.nextInt();
Sample objname= new Sample();
while(nooftestCases>0) {
objname.getDetails();
objname.displayDetails();
nooftestCases--;
}
}
}
答案 0 :(得分:0)
如果我正确理解,您将收到如下输入:
1 2 3 4 5 6
完成后按Enter键。 如果是这种情况,那么您需要将输入解析为字符串并将其拆分为参数:
public static void main(String[] args){
Scanner scanner=new Scanner(System.in);
String input = scanner.nextLine();
String[] arguments = input.split("[ \n]");
System.out.println("First argument:"+arguments[0]);
System.out.println("Last argument:"+arguments[arguments.length - 1]);
//do something with the arguments
}