Question

我按照Youtube教程在Swift中创建了一个选择器视图，如下所示，但是它有一个错误，如该行标题所示：

activityLevelField.inputView = activityPicker

代码：

import UIKit

class ViewController: UIViewController,UIPickerViewDelegate,UIPickerViewDataSource,UITextFieldDelegate {
    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }

    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return activityTypes.count
    }

    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return activityTypes[row]
    }

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        selectedActivity = activityTypes[row]
        activityLevelField.text = selectedActivity
    }

    var selectedActivity: String?
    var activityTypes = ["Less active", "active", "very active"]

    func createActivityPicker(){
        let activityPicker = UIPickerView()

        activityPicker.delegate = self
        activityPicker.dataSource = self

        activityLevelField.inputView = activityPicker
    }

    @IBOutlet weak var activityLevelField: UITextField!

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
        createActivityPicker()
    }
}

Answer 1

您与情节提要的连接断开。从textfiled的连接检查器检查您的连接。

Pickerview主题1：致命错误：展开Op

1 个答案: