Question

这是我的代码：

def start():

    #main input variable to get a sign to do
    calculator = input('What would you like to calculate? (x, /, +, -): ')
    #gets 2 #'s to multiply, add, subtract, or divide 
    if (calculator) == ('+'):
        add = input('what is the frist number would you like to add? ')
        addi = input('what is the second number would you like to add? ')
    elif (calculator) ==('-'):
        sub = input('what is the first number would you like to subtract? ')
        subt = input('what is the second number you would like to subtract? ')
    elif (calculator) == ('/'):
        div = input('what is the first number would you like to divide? ')
        divi = input('what is the second number would you like to divide? ')
    elif (calculator) == ('x'):
        mult = input('what is the first number would you like to multiply? ')
        multi = input('what is the second number would you like to multiply? ')

    #failsafe if done incorrect
    elif (calculator) != ('x', '/', '-', '+'):
        print('try again')
        return


    #adds 2 inputted #'s
    if calculator == '+' :
        sumAdd = float (add) + float (addi)
        print(sumAdd)
    #multiplies the 2 inputted #'s
    elif calculator == 'x' :
        sumMul =  float (mult) * float (multi)
        print(sumMul)
    #divides the 2 inputted #'s
    elif calculator == '/' :
        sumDiv = float (div) / float (divi)
        print(sumDiv)
    #subtracting the 2 inputted #'s
    elif calculator == '-' :
        sumSub = float (sub) - float (subt)
        print(sumSub)

    #returns to top of code to do another setup

    return

start()

这很简单，我明白了。可以返回数字/整数，但我是从头开始做的，对此我感到满意

只是想知道如何在不执行更多代码的情况下获得超过16个小数。还查看是否有比示例更好的值：（float）或（int）来完成这项工作。如果不是很好公开回答您是否有任何疑问谢谢！

Answer 1

编辑：注释正确，format()不准确。

您可以使用decimal模块。

from decimal import *
getcontext().prec = 6 #set the number of decimals you prefer
Decimal(1) / Decimal(7)
>>> Decimal('0.142857')
getcontext().prec = 28
Decimal(1) / Decimal(7)
>>> Decimal('0.1428571428571428571428571429')

Answer 2

尝试使用decimal模块：

from decimal import Decimal, getcontext

# set desired precision, 30 for example
getcontext().prec = 30

# normal
print(1 / 7)
# 0.14285714285714285

# with Decimal
print(Decimal(1) / Decimal(7))
# 0.142857142857142857142857142857

制作一个比16个字符还要精确的程序（例如2/3）

2 个答案: