我正在使用Linux上的MySQL编写一个简单的“ Hello world” JPA Java应用程序。
我正在尝试自动配置架构,从persist.xml调用脚本。
当我尝试实例化我的JPA EntityManagerFactory时出现此错误:
WARN: GenerationTarget encountered exception accepting command : Error executing DDL "CREATE TABLE task (" via JDBC Statement
org.hibernate.tool.schema.spi.CommandAcceptanceException: Error executing DDL "CREATE TABLE task (" via JDBC Statement
at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:67)
at org.hibernate.tool.schema.internal.SchemaCreatorImpl.applySqlString(SchemaCreatorImpl.java:440)
...
Caused by: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:120)
at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:97)
at com.mysql.cj.jdbc.exceptions.SQLExceptionsMapping.translateException(SQLExceptionsMapping.java:122)
at com.mysql.cj.jdbc.StatementImpl.executeInternal(StatementImpl.java:782)
at com.mysql.cj.jdbc.StatementImpl.execute(StatementImpl.java:666)
at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:54)
... 15 more
我已经阅读了其他链接,我尝试显式设置“ MySQL57Dialect”(即使在添加属性之前它也会自动检测到“ MySQL57Dialect”),我尝试简化SQL脚本等。等等-全部无济于事。
版本信息:
Ubuntu 18.04.1 LTS
mysql Ver 14.14 Distrib 5.7.24, for Linux (x86_64) using EditLine wrapper
OpenJDK Runtime Environment (build 10.0.2+13-Ubuntu-1ubuntu0.18.04.4)
SQL脚本(当前的精简版本:从mysql CLI可以正常运行):
CREATE TABLE task (
id BIGINT NOT NULL auto_increment,
summary VARCHAR(20) NOT NULL,
priority VARCHAR(10) NOT NULL DEFAULT 'NORMAL',
status VARCHAR(10) NOT NULL DEFAULT 'PENDING',
created_on TIMESTAMP DEFAULT current_timestamp,
PRIMARY KEY(id)
);
persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="com.example.hellohibernate.jpa" transaction-type="RESOURCE_LOCAL">
<class>com.example.hellohibernate.Task</class>
<class>com.example.hellohibernate.TaskUpdate</class>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL57Dialect" />
<!-- Configuring The Database Connection Details -->
<property name="javax.persistence.jdbc.driver" value="com.mysql.cj.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/test2" />
<property name="javax.persistence.jdbc.user" value="test" />
<property name="javax.persistence.jdbc.password" value="test123" />
<!-- First time only, create from schema: -->
<property name="javax.persistence.schema-generation.database.action" value="create" />
<property name="javax.persistence.schema-generation.create-source" value="script"/>
<property name="javax.persistence.schema-generation.create-script-source" value="META-INF/mkdb.mysql.sql" />
</properties>
</persistence-unit>
</persistence>
控制台日志:
Jan 12, 2019 11:59:54 AM org.hibernate.dialect.Dialect <init>
INFO: HHH000412: Hibernate Core {5.4.0.Final}
...
INFO: HHH000400: Using dialect: org.hibernate.dialect.MySQL57Dialect
...
WARN: GenerationTarget encountered exception accepting command : Error executing DDL "create table task (" via JDBC Statement
org.hibernate.tool.schema.spi.CommandAcceptanceException: Error executing DDL "create table task (" via JDBC Statement
at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:67)
...
Caused by: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:120)
at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:97)
at com.mysql.cj.jdbc.exceptions.SQLExceptionsMapping.translateException(SQLExceptionsMapping.java:122)
at com.mysql.cj.jdbc.StatementImpl.executeInternal(StatementImpl.java:782)
at com.mysql.cj.jdbc.StatementImpl.execute(StatementImpl.java:666)
at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:54)
... 15 more
有什么建议吗?
答案 0 :(得分:1)
我尝试验证MySQL语法,尝试验证MySQL版本,尝试显式设置Hibernate MySql57Dialect,尝试“简化” SQL语法...无济于事。
我基本上尝试了此链接中的所有内容(以及更多):
GenerationTarget encountered exception accepting command : Error executing DDL via JDBC Statement
然后,比尔·卡文(Bill Karwin)建议将每条陈述准确地放在一行上。
DID 有效。
最终-工作-语法:
Java应用程序:
public static final String PERSISTENCE_UNIT = "com.example.hellohibernate.jpa";
protected static EntityManagerFactory entityManagerFactory;
protected static EntityManagerFactory createEntityManagerFactory() {
entityManagerFactory = Persistence.createEntityManagerFactory(PERSISTENCE_UNIT);
...
persistence.xml:
<persistence-unit name="com.example.hellohibernate.jpa" transaction-type="RESOURCE_LOCAL">
<class>com.example.hellohibernate.Task</class>
<class>com.example.hellohibernate.TaskUpdate</class>
<properties>
<!-- Configuring The Database Connection Details -->
<property name="javax.persistence.jdbc.driver" value="com.mysql.cj.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/test2" />
<property name="javax.persistence.jdbc.user" value="test" />
<property name="javax.persistence.jdbc.password" value="test123" />
<!-- First time only, create from schema: -->
<property name="javax.persistence.schema-generation.database.action" value="create" />
<property name="javax.persistence.schema-generation.create-source" value="script"/>
<property name="javax.persistence.schema-generation.create-script-source" value="META-INF/mkdb.mysql.sql" />
...
mkdb.mysql.sql:
drop table if exists task_update;
drop table if exists task;
-- priority: LOW, NORMAL, HIGH
-- status: PENDING, INPROGRESS, COMPLETED, BLOCKED, REOPENED
create table task ( id int NOT NULL auto_increment, summary varchar(20) NOT NULL, priority varchar(10) NOT NULL default 'NORMAL', status varchar(10) NOT NULL default 'PENDING', date timestamp default current_timestamp, PRIMARY KEY(id));
create table task_update ( id int NOT NULL auto_increment, taskid int NOT NULL, text varchar(255) NULL, date timestamp default current_timestamp, PRIMARY KEY(id), FOREIGN KEY fk_task(taskid) REFERENCES task(id));
注意:
注释和空行可以解析OK ...,但是使用Hibernate / JPA解析器(org.hibernate.tool.schema.internal
)将语句拆分为多行似乎会失败。
条例草案-再次感谢您。如果您想发表您的想法,我很乐意“接受”您的想法。否则,我想记录一下发现的结果。