Question

是否可以同时使用{% blocktrans %}“与”和“计数”？

文档仅描述了单独使用：

{% blocktrans with foo|filter as bar and baz|filter as boo %}
{% blocktrans count var|length as count %}

我需要打印一个变量的值，并且转换依赖于另一个变量。我尝试了以下代码：

{% blocktrans count cnt as count with cnt|make_text_from_count as text_count %}
    and other {{ text_count }} city
{% plural %}
    and other {{ text_count }} cities
{% endblocktrans %}

它显示text_count变量的值，但不翻译文本。

Python 2.6.6，Django 1.3，django-templates。

Answer 1

是的，有可能。您只需要注意blocktrans参数的顺序：with需要在它之后立即绑定局部变量，count及其各自的变量绑定在此之后。

documentation（至少1.5版本）有几个复数示例。第二个示例（作为“更复杂的示例”引入）显示了使用with和count时的顺序：

{% blocktrans with amount=article.price count years=i.length %}
That will cost $ {{ amount }} per year.
{% plural %}
That will cost $ {{ amount }} per {{ years }} years.
{% endblocktrans %}

如果您不需要除计数器之外的任何其他变量，请不要使用关键字with。这在上面记录的第一个例子中显示了更为复杂的一个：

{% blocktrans count counter=list|length %}
There is only one {{ name }} object.
{% plural %}
There are {{ counter }} {{ name }} objects.
{% endblocktrans %}

Answer 2

http://docs.djangoproject.com/en/dev/topics/i18n/internationalization/#blocktrans-template-tag

{% blocktrans with text_count=cnt|make_text_from_count count cnt=cnt %}
    and another city
{% plural %}
    and other {{ text_count }} cities
{% endblocktrans %}

使用带有“with”和“count”关键字的blocktrans

2 个答案: