Question

我正在使用PHP在本地计算机上设置一个编辑用户页面。出现此错误

警告：第79行{<?php foreach ($user as $key => $value) : ?>）的foreach（）提供了无效的参数

我试图解决它，但是徒劳。我对PHP有点陌生。也许我缺少或看不到某些东西。如果需要，请协助并纠正我。以下是来自update.php页面的代码。

<?php 

 ini_set('display_errors', '1');
 ini_set('display_startup_errors', '1');
 error_reporting(E_ALL);
 include_once 'core/init.php'; 
 require 'common.php'; //Escapes HTML for output
if (isset($_POST['submit'])) { 

try{
      $this->dbh = new PDO($dsn, $this->user, $this->pass, $options);

$user = [
      "id"        => $_POST['id'],
      "username"  => $_POST['username'],
      "email"     => $_POST['email'],
      "join_date" => $_POST['join_date']
    ];

 $DB->query ('UPDATE users 
        SET id = :id, 
        username = :username, 
        email = :email, 
        join_date = :join_date
        WHERE id = :id');

$DB->execute();

}
catch(PDOException $e){

    echo $this->error = $e->getMessage();
 }

}

if (isset($_GET['id'])) {

    try{
         $this->dbh = new PDO($dsn, $this->user, $this->pass, $options);

         $id = $_GET['id'];

         $DB->query('SELECT * FROM users WHERE id = :id');

         $DB->bind(':id', $id);

         $DB->execute();

         $result=$DB->resultset();

        // Catch any errors
        }
        catch(PDOException $e){

           echo $this->error = $e->getMessage();

        }
    }


?>

<?php include "templates/header.php"; ?>


<?php if (isset($_POST['submit']) && $DB) : ?>

    <blockquote><?php echo escape($_POST['username']); ?> successfully updated.</blockquote>

<?php endif; ?>

<h2>Edit a user</h2>

<form method="post">

    <?php foreach ($user as $key => $value) : ?>

      <label for="<?php echo $key; ?>"><?php echo ucfirst($key); ?></label>

        <input type="text" name="<?php echo $key; ?>" id="<?php echo $key; ?>" value="<?php echo escape($value); ?>" <?php echo ($key === 'id' ? 'readonly' : null); ?> >

<?php endforeach; ?> 



 <input type="submit" name="submit" value="Submit">
</form>

<a href="http://localhost/form/home.php">Back to home</a>

<?php include "templates/footer.php"; ?>

Answer 1

您没有为变量$ user设置任何初始加载值，因此在foreach中未定义该值，因此请使用

  $user = [];
  if (isset($_POST['submit'])) { 

    try{

或者检查并设置$ user的值

   <?php foreach ($user ?? [] as $key => $value) : ?>

如何解决警告：为foreach（）提供的参数无效

1 个答案: