DB2-如何查找计数多次出现的列值

Question

我是DB2的新手，并根据一些类似的文章进行了尝试，我有一个表格，我需要根据status = P和  （primary = 1）的计数超过一次。 所以我的结果应该是2-（9876,3456） 尝试过：

SELECT id, COUNT(isprimary) Counts
  FROM table 
 GROUP BY id
HAVING COUNT(isprimary)=1;

Answer 1

您很亲密，我想您需要做的就是添加一个where子句，如：

SELECT id, COUNT(*) as Counted
FROM table 
WHERE PrimaryFlag = 1 
  AND[status] = 'P'
GROUP BY id

编辑：如果只需要计算不同的ID，请尝试：

SELECT COUNT(t.ID) FROM
(
    SELECT id, COUNT(*) as Counted
    FROM table 
    WHERE PrimaryFlag = 1 
      AND[status] = 'P'
    GROUP BY id
) as t

Answer 2

请尝试以下查询：

select ID as IDs,Count(isPrimary) as isPrimary
From Table
where Status = 'p' 
Group by ID
Having Count(isPrimary) >1