Question

我有一个按照以下方式组织的用于铁路车辆的数据框。我想按['Railroad']进行计数，但前提是它与“ VER”匹配。如果没有，我希望“铁路”将值重新分配为“不”并以此计数。

数据框层次结构：

df1 = df.reset_index().groupby(['Homebase','FINAL ETA','Code Description','L_E', 'Railroad'])['Code Description'].size()

示例输出：

Homebase    FINAL ETA   Code Description        L_E  Railroad   
Rail2       2018-12-06  Arrival in yard         L    VER          1
            2019-01-04  Arrival in yard         L    VER         10
            2019-01-08  Arrival in yard         L    FIL         16
            2019-01-09  Arrival in yard         L    FIL          5
            2019-01-13  Arrival in yard         L    PAS          1

所需的输出：

Homebase    FINAL ETA   Code Description        L_E  Railroad
Rail2       2018-12-06  Arrival in yard         L    VER          1
            2019-01-04  Arrival in yard         L    VER         10
            2019-01-08  Arrival in yard         L    NOT         16
            2019-01-09  Arrival in yard         L    NOT          5
            2019-01-13  Arrival in yard         L    NOT          1

Answer 1

似乎只有铁路栏目正在改变，请尝试以下操作：

ver = (df1['Railroad'] == 'VER')
df1['Railroad'] = 'NOT'
df1.loc[ver, 'Railroad'] = 'VER'

如果不匹配，则数据框分配一揽子标准

1 个答案: