Question

这是一个登录系统，用户输入其详细信息，然后此代码验证用户是否存在

counter = 0
def validation():
    global counter
    print("Sorry, this username or password does not exist please try again")
    counter += 1
    if counter == 3:
        print("----------------------------------------------------")
        print("You have been locked out please restart to try again")
        sys.exit()

def verify_login(username, password, login_data):
    for line in login_data:
       if ("username: " + username + " password: " + password) == line.strip():
       return True

    return False


check_failed = True
while check_failed:
    with open("accountfile.txt","r") as username_finder:
        print("Could player 1 enter their username and password")
        username1=input("Please enter your username ")
        password1=input("Please enter your password ")
        if verify_login(username1, password1, username_finder):
            print("you are logged in")

现在，代码在文本文件中查找以下格式：

username: (username) password: (password)

但是现在我想为每个用户添加一个哈希码，以便文件中的格式如下：

49ad2322f9a401e9e3c4ae7694b6b1f1 username: (username) password: (password)

我如何更改verfiy_login以使其随机查找32 每个用户开头的字符？

Answer 1

与其使用"username: " + username + " password: " + password来重建行，然后将其与文本文件中的行进行比较，还可以通过首先split设置字符串然后解压缩标记来对其进行解析。通过拆分行，您可以分别访问哈希，用户名和密码作为变量。

def verify_login(username, password, login_data):
    for line in login_data:

       hsh, _, username_from_file, _, password_from_file = line.strip().split()
       if len(hsh) == 32 and username == username_from_file and password == password_from_file:
            return True

    return False

将令牌解包到_中是一种惯例，它表示“我们将转储该值”。

Python登录验证系统

1 个答案: