进行销毁以避免重复

Question

是否有一种方法可以避免第5行和第6行中的competenceList[competenceKey]（对象）重复，而在不使用变量声明的情况下保持相同的对象返回？

const func = ({
    entities: { competence: competenceList },
    timesheet: { management: { competences: competenceKey } },
}) => ({
    employeeKey: competenceList[competenceKey].employee,
    payrollEnd: competenceList[competenceKey].competenceEnd,
});

Answer 1

是的，使用计算所得的属性名称在技术上是可行的：

const func = ({
    timesheet: { management: { competences } },
    entities: { competence: { [competences]: competence },
}) => ({
    employeeKey: competence.employee,
    payrollEnd: competence.competenceEnd,
});

但是我不建议您这样做，因为它不太可读。只是写

function func({timesheet, entities}) {
    const competence = entities.competence[timesheet.management.compentences];
    return {
        employeeKey: competence.employee,
        payrollEnd: competence.competenceEnd,
    };
}