Question

我有一个类似这样的变量的XML，其中“ FatturaElettronicaBody”可以出现1次以上：

$variable = '<Root>
<FatturaElettronicaBody>
        <DatiGenerali>
            <DatiGeneraliDocumento>
                <TipoDocumento>TD01</TipoDocumento>
                <Divisa>EUR</Divisa>
                <Data>2018-12-31</Data>
                <Numero>2140/18</Numero>
                <ImportoTotaleDocumento>1843.71</ImportoTotaleDocumento>
                <Causale>FATTURA DIFFERITA VENDITA</Causale>
            </DatiGeneraliDocumento>
            <Attachment>
              <Filename>Test-1.pdf</Filename>
              <Base64File>nfsofsedfmskd=.......</Base64File>
            </Attachment>
            <Attachment>
              <Filename>Test-2.pdf</Filename>
              <Base64File>nfsogfdgdfgdfsffsdgsmskd=.......</Base64File>
            </Attachment>
            ...
         </DatiGenerali>
</FatturaElettronicaBody>
<FatturaElettronicaBody>
        <DatiGenerali>
            <DatiGeneraliDocumento>
                <TipoDocumento>TD01</TipoDocumento>
                <Divisa>EUR</Divisa>
                <Data>2018-10-29</Data>
                <Numero>2094/18</Numero>
                <ImportoTotaleDocumento>500.43</ImportoTotaleDocumento>
                <Causale>FATTURA VENDITA</Causale>
            </DatiGeneraliDocumento>
            <Attachment>
              <Filename>Test-N.pdf</Filename>
              <Base64File>nfsogdhswvervsv.......</Base64File>
            </Attachment>
         </DatiGenerali>
</FatturaElettronicaBody>
...
</Root>
';

我的目标是在XML内搜索“ Numero”节点，并获取父节点“ DatiGeneraliDocumento”以显示有关找到的项目的信息。

例如，我需要找到Numero =“ 2094/18”并在其“ DatiGeneraliDocumento”节点内打印所有信息。在此示例中：

TipoDocumento = TD01
Divisa = EUR
Data = 2018-10-29
ImportoTotaleDocumento = 500.43
Causale = FATTURA VENDITA

PHP中是否有一个函数可以不循环我所有的$ variable？

更新：我已经修改了我的第一个请求，以同时获得“附件”节点：

例如，我需要找到Numero =“ 2094/18”并在其“ DatiGeneraliDocumento”节点和所有“ Attachment”中打印所有信息。在此示例中：

TipoDocumento = TD01
Divisa = EUR
Data = 2018-10-29
ImportoTotaleDocumento = 500.43
Causale = FATTURA VENDITA

Filename = Test-1.pdf
Base64File = nfsofsedfmskd=

Filename = Test-2.pdf
Base64File = nfsogfdgdfgdfsffsdgsmskd=

我尝试过运气：

$numeroFattura = "2094/18";

foreach ($xml->xpath('//DatiGenerali[Numero = "' . $numeroFattura . '"]') as $x) {
  foreach($x as $v) {
    echo $v->getName() .'='. $v ."<br>\n";
  }
}

//  GET ATTACHMENT  <---this doesn't work

foreach ($xml->xpath('//FatturaElettronicaBody[Numero = "' . $numeroFattura . '"]') as $x) {
    foreach ($x->xpath('//Allegati') as $allegato) {
        var_dump($allegato);
    }
}

Answer 1

您可以使用PHP DOMDocument和DOMXPath提取所需的信息。通过在XPath查询中为Numero指定节点值，我们仅获得您感兴趣的节点：

$doc = new DOMDocument();
$doc->loadXML($variable);
$xpath = new DOMXPath($doc);
$nodes = $xpath->query("//DatiGeneraliDocumento[Numero='2094/18']");
foreach ($nodes as $nodelist) {
    foreach ($nodelist->childNodes as $node) {
        if ($node->nodeType === XML_ELEMENT_NODE) echo $node->nodeName . " = " . $node->nodeValue . "\n";
    }
}

输出：

TipoDocumento = TD01 
Divisa = EUR 
Data = 2018-10-29 
Numero = 2094/18 
ImportoTotaleDocumento = 500.43 
Causale = FATTURA VENDITA

Demo on 3v4l.org

Answer 2

使用simplexml

  displayedColumns: string[] = ['name', 'email', 'phone', 'customColumn'];

demo

在XML内查找节点并获取父注释

2 个答案: