Question

public function webhook() 
{
    $webhook_endpoint_secret = env("GOCARDLESS_WEBHOOK_ENDPOINT_SECRET");
    $request_body = file_get_contents('php://input');

    $headers = getallheaders();
    $signature_header = $headers["Webhook-Signature"];

    try {
        $events = Webhook::parse($request_body, $signature_header, $webhook_endpoint_secret);

        foreach ($events as $event) {
            print("Processing event " . $event->id . "\n");

            switch ($event->resource_type) {
                case "mandates":
                    $this->process_mandate_event($event);
                    break;
                default:
                    print("Don't know how to process an event with resource_type " . $event->resource_type . "\n");
                    break;
            }
        }

        header("HTTP/1.1 204 OK");
    } catch(InvalidSignatureException $e) {
        header("HTTP/1.1 498 Invalid Token");
    }
}


public function process_mandate_event($event)
{
    switch ($event->action) {
        case "cancelled":
            print("Mandate " . $event->links["mandate"] . " has been cancelled!\n");
            break;
        default:
            print("Don't know how to process a mandate " . $event->action . " event\n");
            break;
    }
}

如何检查列表中的值是否大于def fun_lst(lst, a, b): if min(lst)<b and max(lst)>a: return True return False但小于a？我尝试了上面的方法，但在此示例中：b该函数返回fun_lst([-1, 3.5, 6], -2.4, 0)，它应该返回True。

Answer 1

执行以下操作：

def foo
rescue
end

输出：

def fun_lst(lst, a, b):
    if min(lst) > a and max(lst) < b:
        return True
    return False

print(fun_lst([-1, 3.5, 6], -2.4, 0) )

进行False可以确保每个元素比一个元素更大。
进行min(lst) > a可以确保每个元素比b 小。

替代解决方案：

max(lst) < b

Answer 2

如果愿意的话，您可以尝试这款内胆

all([num < b and num > a for num in lst])

Answer 3

此处的代码将检查列表中的每个项目，如果找到一个不大于a且小于b的项目，则返回false，否则返回true。

def fun_lst(lst, a, b):
    for item in lst:
        if not a < item < b:
            return False
    return True

Answer 4

myList = [1,2,3,4,5,6,7,8,9]
lower_limit = 3
upper_limit = 8
bool_output = all([i > lower_limit and i < upper_limit for i in myList])
print(bool_output)
    False

myList = [1,2,3,4,5,6,7,8,9]
lower_limit = 0
upper_limit = 10
bool_output = all([i > lower_limit and i < upper_limit for i in myList])
print(bool_output)
    True

Answer 5

您应该尝试以下操作：

def fun_lst(lst, a, b):
    return all(n > a and n < b for n in lst)

Answer 6

如果您准备使用numpy，请尝试

In [1]: import numpy as np

In [3]: np.array(b)
Out[3]: array([ 3,  1,  4, 66,  8,  3,  4, 56])

In [17]: b[(2<b) & (b<5)]
Out[17]: array([3, 4, 3, 4])

Answer 7

不同的方法：

def fun_lst(lis, x, y):
    list = [i>x and i<y for i in lis]
    return False if False in list else True

这很简单：

def fun_lst(lis, x, y):
    return x<max(lis)<y

lambda版本：

fun_lst = lambda lis, x, y: x<max(lis)<y

输出：

fun_lst([-1, 3.5, 6], -2.4, 0) #Output: False

检查列表中的所有值是否都大于特定数字x且小于y？

7 个答案:

执行以下操作：

替代解决方案：