要并排合并两个数组，我遵循以下过程，但得到
无法设置未定义的属性“帐户”。
这是我的代码
//MARK: - Multiple Images Uploading API Call
func serviceUploadMultipleImageData(model : UploadImageResponseModel,isLoader:Bool = true,name:String = "", loaderViewcontoller : UIViewController? = nil,url: String, method: HTTPMethod, InputParameter: Parameters?, ServiceCallBack: @escaping (_ Completion: ServiceResponseNormal, _ isSuccess:Bool)-> Void) {
let viewContoller = loaderViewcontoller
guard Reachability.isConnectedToNetwork() else {
Singleton.sharedSingleton.showPopup(title: "No Internet", message: HttpCode.NoInternetConnection.message(), image: nil, VC: viewContoller!)
ServiceCallBack(self.setCustomResponse(Code: HttpCode.NoInternetConnection.rawValue, Message: "No Internet Connection"),false)
return
}
if isLoader == true {
if viewContoller != nil {
ProgressHUD.startLoading(onView: (viewContoller?.view)!)
} else {
ProgressHUD.startLoading(onView: appDelegate.window!)
}
}
Alamofire.upload(multipartFormData: { (multipartFormData) in
for obj in model.arrImages{
multipartFormData.append(obj.imageData!, withName:obj.imgName, fileName: "", mimeType: "image/jpg")
}
for (key, value) in InputParameter! {
multipartFormData.append((value as AnyObject).data(using: String.Encoding.utf8.rawValue, allowLossyConversion: true)!, withName: key)
}
}, to:url)
{ (result) in
switch result {
case .success(let upload, _, _):
upload.uploadProgress(closure: { (Progress) in
model.progress = Progress.fractionCompleted
})
upload.responseJSON { response in
if isLoader == true {
if viewContoller != nil {
ProgressHUD.stopLoading(fromView: (viewContoller?.view)!)
}else {
ProgressHUD.stopLoading(fromView: appDelegate.window!)
}
}
if(response.result.isSuccess){
print(response)
do{
if response.data != nil{
var responseParsed = try JSONDecoder().decode(ServiceResponseNormal.self, from: response.data!)
if responseParsed.Code == "200"
{
responseParsed.Data = response.data
ServiceCallBack(responseParsed, true)
}
else
{
Singleton.sharedSingleton.showPopup(title: "Error", message: responseParsed.Message ?? "Error", image: nil, VC: viewContoller!)
ServiceCallBack(responseParsed, false)
}
}
}
catch let error {
print(error.localizedDescription)
var falilure = ServiceResponseNormal()
falilure.Data = nil
falilure.Message = "Response could not parsed"
ServiceCallBack(falilure, false)
}
}
else{
if let error = response.result.error{
let message = error.localizedDescription
var falilure = ServiceResponseNormal()
falilure.Data = nil
falilure.Message = message
ServiceCallBack(falilure, false)
Singleton.sharedSingleton.showPopup(title: "Error", message: message, image: nil, VC: viewContoller!)
}
}
}
case .failure(let encodingError):
let message = encodingError.localizedDescription
var falilure = ServiceResponseNormal()
falilure.Data = nil
falilure.Message = message
ServiceCallBack(falilure, false)
Singleton.sharedSingleton.showPopup(title: "Error", message: message, image: nil, VC: viewContoller!)
}
}
}
如果我这样添加 acs = [
{
"account": "Cash In Hand",
"liabilities": 0,
"assets": 8031597
},
{
"account": "Tax Acs",
"liabilities": 988363.72,
"assets": 0.98
},
{
"account": "Sundry Debtor",
"liabilities": 0,
"assets": 551
},
{
"account": "Sundry Creditor",
"liabilities": 0,
"assets": 0
}
];
acd: any;
acc: any;
newacc: any;
constructor() { }
ngOnInit() {
this.acd = this.acs.filter(f => f.liabilities !== 0);
this.acc = this.acs.filter(f => f.assets !== 0);
const bigger = this.acd.length > this.acc.length ? this.acd.length : this.acc.length;
this.newacc = [];
for (let i = 0; i < bigger; i++) {
if (this.acd.length > i) {
this.newacc[i].account = this.acd[i].account;
this.newacc[i].liabilities = this.acd[i].liabilities;
}
if (this.acc.length > i) {
this.newacc[i].accounts = this.acc[i].account;
this.newacc[i].assets = this.acc[i].assets;
}
}
}
，第二个this.newacc = [{}];也会收到相同的错误，即if
我在这里犯了什么错误？还是有最简单的方法将两个数组并排组合？这两个数组在数组长度上是独立的，并且不进行任何连接。
答案 0 :(得分：0)
您应该使用push方法。问题是您要使用C++这样的语法添加元素。
this.newacc[i].account = this.acd[i].account;
如前所述，可以通过传递所需的 object 作为参数来使用push方法。
newacc.push({account:acd[i].account, liabilities : acd[i].liabilities });
acs = [ { "account": "Cash In Hand", "liabilities": 0, "assets": 8031597 }, { "account": "Tax Acs", "liabilities": 988363.72, "assets": 0.98 }, { "account": "Sundry Debtor", "liabilities": 0, "assets": 551 }, { "account": "Sundry Creditor", "liabilities": 0, "assets": 0 } ];
acd = acs.filter(f => f.liabilities !== 0);
acc = acs.filter(f => f.assets !== 0);
const bigger = acd.length > acc.length ? acd.length : acc.length, newacc = [];
for (let i = 0; i < bigger; i++) {
if (acd.length > i)
newacc.push({account:acd[i].account, liabilities : acd[i].liabilities });
if (acc.length > i)
newacc.push({account:acc[i].account, assets : acc[i].assets });
}
console.log(newacc);
答案 1 :(得分：0)
您的问题纯粹是一个Typescript问题，其中没有棱角。
这是部分代码的修复程序，其余的我想您可以弄清楚：
interface accnt {
account: string;
liabilities: number;
assets: number;
}
let acs = [
{
"account": "Cash In Hand",
"liabilities": 0,
"assets": 8031597
},
{
"account": "Tax Acs",
"liabilities": 988363.72,
"assets": 0.98
},
{
"account": "Sundry Debtor",
"liabilities": 0,
"assets": 551
},
{
"account": "Sundry Creditor",
"liabilities": 0,
"assets": 0
}
];
let acd: accnt[] = new Array(4);
let acc: accnt[] = new Array(4);
let newacc: accnt[] = new Array(4);
this.acd = this.acs.filter(f => f.liabilities !== 0);
this.acc = this.acs.filter(f => f.assets !== 0);
alert(JSON.stringify(this.acd));
alert(JSON.stringify(this.acc));
alert(JSON.stringify(this.newacc));
const bigger = this.acd.length > this.acc.length ? this.acd.length : this.acc.length;
for (let i = 0; i < bigger; i++) {
if (this.acd.length > i) {
this.newacc[i] =
{
account: this.acd[i].account,
liabilities: this.acd[i].liabilities
}
}
/*if (this.acc.length > i) {
this.newacc[i].accounts = this.acc[i].account;
this.newacc[i].assets = this.acc[i].assets;
}*/
}
alert(JSON.stringify(this.newacc));