表结构:
$scope.splitMerchants =[
{id: 1, label: 'Edit'},
{id: 2, label: 'Open'},
{id: 3, label: 'Close'},
{id: 4, label: 'Close1'},
{id: 5, label: 'Close2'},
{id: 6, label: 'Close3'},
{id: 7, label: 'Close4'}
];
$scope.currentPage = 1;
$scope.page = $scope.splitMerchants[0];
$scope.paginationPreviousButton = function(){
$scope.currentPage--;
if ($scope.currentPage <= 0) {
$scope.currentPage = 1;
}
$scope.page = $scope.splitMerchants[$scope.currentPage-1];
};
$scope.paginationNextButton = function() {
$scope.currentPage++;
if($scope.currentPage > $scope.splitMerchants.length) {
$scope.currentPage = $scope.splitMerchants.length;
}
$scope.page = $scope.splitMerchants[$scope.currentPage-1];
};
$scope.paginationDropdownChange = function(page) {
$scope.currentPage = page.id;
};
以下是我对上表的查询:
ID NAME SUM_HOURS WEEK
1 name1 32 2018-01-01
1 name1 30 2018-02-01
1 name1 35 2018-03-01
所需的表结构:
SELECT id id,
e.name name,
SUM(f.hours) sum_hours,
fc.from_date week,
FROM factdaily f, finance_calendar_full fc, employee e
WHERE f.date = fc.date
AND f.emp_id = e.id
AND f.date >= valid_from
AND f.date <= valid_to
GROUP BY week
HAVING sum_hours > 0
由于我无法弄清任何帮助,因此深表感谢。