Question

我在data have; do _n_ = 1 to 1000; key1 = ceil (10 * ranuni(123)); key2 = ceil (10 * ranuni(123)); key3 = ceil (10 * ranuni(123)); sat1 = 100 + ceil (4 * ranuni(123)); sat2 = 100 + ceil (4 * ranuni(123)); output; end; run; proc sql; * result set for distinct rows -- some key repetition still present; create table distinct_all as select distinct * from have ; * result set for distinct keys -- fewer than distinct rows; create table keys as select distinct key1,key2,key3 from have ; * result for distinct keys with an arbitrary row amongst the repeateds; create table distinct_key_arb_sat(drop=seq) as select key1, key2, key3, sat1, sat2, monotonic() as seq from have group by key1, key2, key3 having seq = min(seq) ;平面上有6个点：(x,y)和x=[x1,x2,x3,x4,x5,x6]

y=[y1,y2,y3,y4,y5,y6]

我想在两点之间，在每个轴import matplotlib.pyplot as plt x = [0, 2, 4, 0, 2, 4, 0, 2, 4] y = [0, 0, 0, 3, 3, 3, 7, 7, 7] plt.scatter(x, y) plt.show()上绘制完全平行的线（例如photo）。以及如何在图表上隐藏x和y轴。我想绘制3层建筑的梁和柱的2D视图；是x,y达到我的目标还是应该去其他图书馆？

Answer 1

绝对matplotlib可以做到这一点。看看他们的Rectangle Patch：

示例用法（您必须根据需要对其进行修改）

import matplotlib.pyplot as plt
import matplotlib.patches as patches

fig = plt.figure()
ax = fig.add_subplot()

rect = patches.Rectangle(
    (0.1, 0.1),
    0.5,
    0.5,
    fill=False
)
ax.add_patch(rect)
fig.show()

在python中的点之间绘制网格线

1 个答案: