在Matplotlib中更改3D图中的视点

Question

我正在尝试更改3D图的视图，好像我正站在红点处，朝绿线方向看。将视图的方位角设置为等于坡度时要注意方向。但是，缩放到红点级别是一个问题。我知道ax.dist是关键，但是我不知道如何正确使用它。如果红点不在图的中间，则经过一定程度的缩放后，红点将从视图中消失。

这是代码

import numpy as np  
import matplotlib.pyplot as plt  

fig = plt.figure()  
ax = fig.gca(projection='3d')  

def set_axes_equal(ax):  
    '''Make axes of 3D plot have equal scale so that spheres appear as spheres,
    cubes as cubes, etc..  This is one possible solution to Matplotlib's
    ax.set_aspect('equal') and ax.axis('equal') not working for 3D.

    Input  
      ax: a matplotlib axis, e.g., as output from plt.gca().  
    '''  

    x_limits = ax.get_xlim3d()  
    y_limits = ax.get_ylim3d()  
    z_limits = ax.get_zlim3d()

    x_range = abs(x_limits[1] - x_limits[0])  
    x_middle = np.mean(x_limits)  
    y_range = abs(y_limits[1] - y_limits[0])
    y_middle = np.mean(y_limits)
    z_range = abs(z_limits[1] - z_limits[0])
    z_middle = np.mean(z_limits)

    # The plot bounding box is a sphere in the sense of the infinity
    # norm, hence I call half the max range the plot radius.
    plot_radius = 0.5*max([x_range, y_range, z_range])  

    ax.set_xlim3d([x_middle - plot_radius, x_middle + plot_radius])
    ax.set_ylim3d([y_middle - plot_radius, y_middle + plot_radius])
    ax.set_zlim3d([z_middle - plot_radius, z_middle + plot_radius])  



y1 = range(20)  
x1 = [1] * len(y1)  
x2 = np.array(range(11))
y2 = -x2 + 10
x3 = np.array(range(1, 9))
y3 = x3 * 2
z3 = range(len(x3))
x4 = range(6, 10)
y4 = [12.5] * len(x4)
y5 = range(20)
x5 = [15] * len(y5)  

ax.plot(x1, y1, color = 'y')  
ax.plot(x2, y2, color = 'g')
ax.plot([5], [5], [0], 'or', markersize = 4)
ax.plot(x3, y3, z3, color = 'm')
ax.plot(x4, y4, color = 'b')
ax.plot(x5, y5, color = 'c')


set_axes_equal(ax)  
ax.set_xlabel("x")  
ax.set_ylabel("y")  
azi = np.degrees(np.arctan((x2[-1]-x2[0])/(y2[-1]-y2[0])))
ax.view_init(elev = 10, azim = azi)
ax.dist = 10

plt.show()  

set_axes_equal(ax)来自here。

如何在视图中保留红点以及如何计算准确的ax.dist值？