使用PHP从表1获取申请人并比较ID和从表2获取用户详细信息

Question

好，所以我有两个表

1. 申请人列表-显示所有申请人

1. 用户表

现在我要通过Post方法提供news_id，我想列出所有users(email,mobile,username)的详细信息，其中 user_authToken 和 user_authtoken 的值是同样的。有人可以使用 PHP 帮助我解决这个问题吗？

       $job_id = $_POST['job_id'];
       $resultSet = $con->query("SELECT appliers_list.news_id  AS jobid ,
       appliers_list.user_authToken AS user,
       user.user_name AS username,
       user.mobile AS mobile,
       FROM appliers_list,user 
       WHERE  appliers_list.news_id = '$job_id'
       ORDER BY appliers_list.id DESC
       ");
       $rows = $resultSet->fetch_assoc();

Answer 1

• 首先，您的命名非常不一致，很难阅读和理解。

• 第二，请使用prepare语句，否则您将系统打开以进行SQL注入。

  $news_id = $_POST['job_id'];
  
  $stmt = $con->prepare("SELECT email, mobile, user_name
  FROM users 
  WHERE user_authtoken in (select user_authToken from appliers_list where news_id = ?)");
  $stmt->bind_param("i", $news_id);
  $stmt->execute();
  $resultSet = $stmt->get_result();
  
  while($row = $resultSet->fetch_assoc()) {
  // data manipulation here
  }
  

Answer 2

您可以使用左连接从两个表中获取记录：

       $job_id = !empty($_POST['job_id']) ? intval($_POST['job_id']) : 0;
       $resultSet = $con->query("SELECT appliers_list.*,users.email
       FROM appliers_list 
       left join users on appliers_list.user_authToken  = users.user_authToken
       WHERE news.news_id = '$job_id'
       ORDER BY news.id DESC
       ");
       $rows = $resultSet->fetch_assoc();

Answer 3

您未在user和appliers_list表之间指定关系，因此将获得user中的所有行。 SELECT列表的末尾还有一个逗号。

   $job_id = $_POST['job_id'];
   $resultSet = $con->query("SELECT appliers_list.news_id  AS jobid ,
   appliers_list.user_authToken AS user,
   user.user_name AS username,
   user.mobile AS mobile
   FROM appliers_list
   JOIN user ON appliers_list.user_authToken = user.user_authToken
   WHERE  appliers_list.news_id = '$job_id'
   ORDER BY appliers_list.id DESC
   ");
   $rows = $resultSet->fetch_assoc();